필터 지우기
필터 지우기

Changing the radius of the LTP feature extractor in this code

조회 수: 3 (최근 30일)
Faraz
Faraz 2017년 5월 11일
댓글: Maitreyee Mordekar 2017년 5월 19일
Hi,
Ive downloaded the following code for extracting the LTP of an image for classification. The code extracts the LTP code in a circle of radius 2.
% Local ternary patterns
function [high,low,ternary]=ltp_image(in,type,threshold)
[rows,cols]=size(in);
% case 'P8R2' % 8 pixels in a circle of radius 2
% embed input matrix in a larger one, extending with zeros (trim a
% 2 pixel border off of the output matrices if you don't like this)
r=rows+4;
c=cols+4;
A = zeros(r,c);
r0=3:r-2;
c0=3:c-2;
A(r0,c0) = in;
% radius 2 interpolation coefficients for +-45 degree lines
alpha = 2-sqrt(2);
beta = 1-alpha;
% 8 directional derivative images
d0 = A(r0,c0-2) - in;
d2 = A(r0+2,c0) - in;
d4 = A(r0,c0+2) - in;
d6 = A(r0-2,c0) - in;
d1 = alpha*A(r0+1,c0-1) + beta*A(r0+2,c0-2) - in;
d3 = alpha*A(r0+1,c0+1) + beta*A(r0+2,c0+2) - in;
d5 = alpha*A(r0-1,c0+1) + beta*A(r0-2,c0+2) - in;
d7 = alpha*A(r0-1,c0-1) + beta*A(r0-2,c0-2) - in;
% pack derivative images into a single matrix, one per column,
% threshold and code to get output matrices
d = [d0(:),d1(:),d2(:),d3(:),d4(:),d5(:),d6(:),d7(:)];
code = 2.^(7:-1:0)';
high = reshape((d>=threshold)*code,rows,cols);
low = reshape((d<=-threshold)*code,rows,cols);
if nargout>2
code = 3.^(7:-1:0)';
ternary = reshape((d>=threshold)*code+(d<=-threshold)*2*code,rows,cols);
end
%end;
The function tales the input "type", which is unused as it is commented out.
I need to change the radius to 3,6,9 etc. and I cannot find the unedited code of this online. How would I change the radius in this code?
Thank you
  댓글 수: 1
Maitreyee Mordekar
Maitreyee Mordekar 2017년 5월 19일
Hi Faraz,
Could you tell me where did you download this code from? I think the author of this code, will be in a better position to help you.

댓글을 달려면 로그인하십시오.

답변 (0개)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by