my code is
syms y(t);
ode = diff(y,t) == (1-y)*exp(-0.1*y)
ysol(t) = dsolve(ode)
cond = y(0) == .5;
ysol(t) = dsolve(ode,cond)
t=[0:5]
plot(t,cell2mat(double(ysol(t))))
how would i determine the stationary solution in matlab when t approaches to infinity

답변 (1개)

David Goodmanson
David Goodmanson 2017년 4월 20일
편집: David Goodmanson 2017년 4월 20일

0 개 추천

Hello Arslan, (I checked this by ode45 but the principle should be the same). You are solving dy/dt = (1-y)*exp(-.1*y). For a stationary solution, dy/dt = 0. So either exp(-.1*y) = 0 or (1-y) = 0. The first case corresponds to y = inf which is probably not what you are looking for, and the second case should be the solution.

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질문:

2017년 4월 19일

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2017년 4월 20일

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