MATLAB Answers

While loop question in row addition sums. Want row to be less then 2.

조회 수: 1(최근 30일)
tban
tban 9 Apr 2017
I am generating a matrix such as this,
1.0739 0.9517 0.1078 0.4077 0.7066 0.7983
0.6003 1.1885 0.1747 0.3946 0.3541 0.0705
0.7753 0.0929 0.0649 0.0188 0.0298 0.0954
0.4378 0.1140 2.8074 0.5060 0.7248 0.2897
0.1666 0.4086 0.3344 0.0417 0.5798 2.7909
0.0513 1.0805 0.4291 1.3061 0.1078 0.6336
0.5828 0.4903 2.0129 0.5368 0.2691 0.6476
0.1921 0.0626 0.1121 0.1333 0.0121 0.0682
0.2640 0.1722 0.3182 0.2676 1.0384 0.5087
0.5586 0.1019 0.1335 0.4800 0.5046 1.1357
0.2461 0.0407 0.2132 0.7918 0.1956 1.2577
1.4788 0.0586 0.3212 1.1473 0.3263 0.2079
0.2761 2.1830 0.6020 0.5124 0.0489 0.0253
0.0572 0.1084 0.3595 0.1271 0.6155 0.0778
0.2312 0.1831 0.0423 0.1079 0.6713 0.1707
0.2744 0.6776 0.3923 1.0708 0.1322 0.1165
I also have a matrix the same size full of zeros. I want to loop trough every row and sum every value until the next value yields a value above 2.
So a row such as [1.0739 0.9517 0.1078 0.4077 0.7066 0.7983 ...] would loop trough every value and if the sum is not 2 yet, it would rewrite it in the other matrix that is now zeros.
initiate_matrix_z = zeros(16,6);
initiate_matrix_p = %the numbered matrix
for r=1:16 %rows
while (sum <= 2) %note that all sums must be below 2
for c=1:6 %for all values in row
sum = initiate_matrix_p(r,c) + sum %take the value and add it to previous sum
end
end
At the end of this I want the following:
1.0739 0 0 0 0 0 %second value makes sum of row exceed 2
0.6003 1.1885 0.1747 0 0 0 %fourth value makes sum of row exceed 2
0.7753 0.0929 0.0649 0.0188 0.0298 0.0954 %no value makes sum(row)>2
0.4378 0.1140 0 0 0 0 %third value makes sum of row exceed 2

  댓글 수: 2

Image Analyst
Image Analyst 9 Apr 2017
DON'T USE sum AS THE NAME OF YOUR VARIABLE BECAUSE IT'S THE NAME OF A VERY IMPORTANT BUILT IN VARIABLE. Now, do you NEED to use a loop, or can you use cumsum() like the vast majority of good MATLAB programmers would use?
tban
tban 9 Apr 2017
Thanks for the feedback, but too much salt man.

댓글을 달려면 로그인하십시오.

답변(2개)

Image Analyst
Image Analyst 9 Apr 2017
Try this:
m = [...
1.0739 0.9517 0.1078 0.4077 0.7066 0.7983
0.6003 1.1885 0.1747 0.3946 0.3541 0.0705
0.7753 0.0929 0.0649 0.0188 0.0298 0.0954
0.4378 0.1140 2.8074 0.5060 0.7248 0.2897
0.1666 0.4086 0.3344 0.0417 0.5798 2.7909
0.0513 1.0805 0.4291 1.3061 0.1078 0.6336
0.5828 0.4903 2.0129 0.5368 0.2691 0.6476
0.1921 0.0626 0.1121 0.1333 0.0121 0.0682
0.2640 0.1722 0.3182 0.2676 1.0384 0.5087
0.5586 0.1019 0.1335 0.4800 0.5046 1.1357
0.2461 0.0407 0.2132 0.7918 0.1956 1.2577
1.4788 0.0586 0.3212 1.1473 0.3263 0.2079
0.2761 2.1830 0.6020 0.5124 0.0489 0.0253
0.0572 0.1084 0.3595 0.1271 0.6155 0.0778
0.2312 0.1831 0.0423 0.1079 0.6713 0.1707
0.2744 0.6776 0.3923 1.0708 0.1322 0.1165]
[rows, columns] = size(m);
output = zeros(size(m));
for row = 1 : rows
cdf = cumsum(m(row, :))
index = find(cdf < 2, 1, 'last');
cdf(index+1:end) = 0;
output(row, :) = cdf;
end
output % Print to command window

  댓글 수: 0

댓글을 달려면 로그인하십시오.


Walter Roberson
Walter Roberson 9 Apr 2017
temp = cumsum( initiate_matrix_p, 2);
mask = temp < 2;
initiate_matrix_z(mask) = temp(mask);
No loop.

  댓글 수: 0

댓글을 달려면 로그인하십시오.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by