C++ pointers and variables
조회 수: 1 (최근 30일)
이전 댓글 표시
Dear experts,
I am trying to convert the following C++ code to a matlab code:
double buffer = 72.0;
double *pBuffer = &buffer;
t = sizeof(buffer));
Does anyone know to solve this question?
Thank you in advance.
Carlos
댓글 수: 0
채택된 답변
Jan
2017년 4월 3일
buffer = 72;
You do neither need a pointer in Matlab nor does the the size of the type matter.
댓글 수: 4
Guillaume
2017년 4월 4일
If you're using this filexchange sizeof you're using it incorrectly. The correct code should have been:
calllib(libstring,'SetSystemParameter',MAXIMUM_RANGE,pRecord31,sizeof('double'));
Or you could just not have bothered and pass 8 directly, since scalar double are always 8 bytes.
Note that matlab may have been clever enough to automatically make the conversion from double to void pointer, so possibly this may have been enough:
value = 72;
calllib(libstring,'SetSystemParameter',MAXIMUM_RANGE, value, 8)
추가 답변 (0개)
참고 항목
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!