MATLAB Answers

non linear Least square fitting

조회 수: 14(최근 30일)
Xin 19 Nov 2016
댓글: Xin 12 Jun 2020
I have an equation:
z = A*(y^B)*exp(C*x)
where x,y,z are my data points, and A B C are the unknowns that I want to fit.
Is there a way to fit these unknowns with least square function.

채택된 답변

Star Strider
Star Strider 19 Nov 2016
The ‘trick’ here is to create a matrix of your ‘x’ and ‘y’ data vectors and give them to your objective function as a single argument. The objective function can then refer to the appropriate columns of that matrix to use ‘x’ and ‘y’ correctly in your equation. I created random ‘x’, ‘y’, and ‘z’ vectors to test my code, so substitute your data for them. My code would otherwise not change. The estimated parameters are the ‘B’ output of the fminsearch call, the second ‘resnorm’ output being the norm of the residuals. (The ‘resnorm’ output is not necessary, but is helpful in assessing how good the fit is.)
The Code
% % % z = A*(y^B)*exp(C*x) % Original Equation
% % % MAPPING: b(1) = A, b(2) = B, b(3) = C
z_fit = @(b, xy) b(1) .* xy(:,2).^b(2) .* exp(b(3) .* xy(:,1));
x = randi(99, 1, 10); % Create Data
y = randi(99, 1, 10); % Create Data
z = randi(99, 1, 10); % Create Data
xy = [x(:), y(:)]; % Create Column Vectors & Concatenate In One Matrix To Form Independent Variable Argument
NCF = @(b) norm(z - z_fit(b,xy)); % Norm Cost Function
B0 = [1; 2; 3]; % Initial Parameter Estimates
[B,resnorm] = fminsearch(NCF, B0); % Estimate Parameters
You can plot the result using scatter3 or stem3 for your data, and plot3 for the objective function fit. Use the hold function to plot them on the same axes, and grid on to show the grid lines.
  댓글 수: 4
Xin 12 Jun 2020
You need to also provide the function you are trying to fit but based on what I see, you have a problem with the maximum value exceeded, which you can modify using the following line:
options = optimoptions('fmincon','Display','iter','Algorithm','sqp');
options.MaxFunEvals = 1e5;
then you can use options into fmincon or fminsearch.

댓글을 달려면 로그인하십시오.

추가 답변(0개)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by