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Attempted to access x(5); index out of bounds because numel(x)=4.

조회 수: 2 (최근 30일)
lotus whit
lotus whit 2016년 8월 2일
댓글: Image Analyst 2016년 8월 2일
could you please to help me , i have this error when i tried to run this code which calculate distance between two points groups
x = [2,3,4,5];
y = [4,4,5,4];
s_x = size(x);
d2 = (s_x(1,2));
d = zeros(1,4)
for ii=1:1:d2
d(ii) = sqrt((x(ii+1)-x(ii))^2+(y(ii+1)-y(ii))^2);
end
any one have any idea about solution?

답변 (2개)

Image Analyst
Image Analyst 2016년 8월 2일
It looks like you're trying to do this:
x = [2,3,4,5];
y = [4,4,5,4];
deltax = diff(x)
deltay = diff(y)
distances = sqrt(deltax .^2 + deltay .^2)

James Tursa
James Tursa 2016년 8월 2일
편집: James Tursa 2016년 8월 2일
The error is caused by ii iterating from 1 to 4, but you use ii+1 (=5 at last iteration) as an index into the x and y vectors which are only of length 4. For your example, what would you like the desired output to be? I.e., what would the desired values of d be for your example?
  댓글 수: 2
lotus whit
lotus whit 2016년 8월 2일
Thank you about your fast response, i want to calculate the distance between each point in x,y vectors , for example point1(x1,y1) , point2(x2,y2), i need to calculate the distance between point1 and point2 then calculate distance point2 and point3 then point3 and point4 and so on dependent on length of vector(x) and vector(y). thank you again
Image Analyst
Image Analyst 2016년 8월 2일
That's what my code in my Answer does.

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