store images in a table

Hello,

I have three images and want to store them in a table. I wrote this in command line:

dinfo = dir('*.jpg');
T = table();
for K = 1 : length(dinfo)
filename = dinfo(K).name;
filecontent = imread(filename);
T{filename,1} = filecontent;
end

It gives the error:

To assign to or create a variable in a table, the number of rows must match the height of the table.

Secondly, I want to make my three images equal in size, as we have to make the size of variables in rows equal for tables.

Help needed. Thanks in advance.

Answer 1

[Azzi Abdelmalek]

Do you mean how to store them in a cell array?

dinfo = dir('*.jpg');
n=numel(dinfo);
T=cell(n,1);
for K = 1 : n
  filename = dinfo(K).name;
  filecontent = imread(filename);
  T{k,1} = filecontent;
end

Answer 2

[Guillaume]

You've created an empty table (no columns or rows) and are then trying to index into it using row names it knows nothing about. Of course, it's not going to work. The fix is to create a table the right size by passing it a cell array the right size, and telling it the names of the rows at the same time:

numimages = numel(dinfo); %numel is safer than length
T = table(cell(1, numimages), 'VariableNames', {'image'}, 'RowNames', {dinfo.name});
for K = 1 : numimage
  ...

Note that your filenames must be valid variable names otherwise your assignment call will fail. It may be safer to use:

T{K, 1} = filecontent

Since the images are held in a cell array there is no requirement that they are the same size. But if you want that, use imresize