adding constraints with if loop
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a1=1:.3:5.2;
b1=3:.2:5.8;
c1=2:.3:6.2;
for k=1:15
composite=[a1(:,k) b1(:,k) c1(:,k)];
origin=[1.3 1.1 1.5];
d(:,k)=sqrt(sum((composite-origin).^2));% 1*15 vector
end
But now in 'composite' I want to exclude those all points which have a1 less than or equal to 1.5, b1 greater than or equal to 5 and c1 less than or equal to 2. So now my d vector will be 1*6 instead of 1*15. How can I get this result with combination of for and if loop.
댓글 수: 3
Walter Roberson
2012년 2월 4일
'S'ok. I'm just trying to prevent the phrase from spreading as several people started using it.
채택된 답변
Walter Roberson
2012년 2월 4일
And if it must be done with "for" and "if" then,
a1=1:.3:5.2;
b1=3:.2:5.8;
c1=2:.3:6.2;
origin=[1.3 1.1 1.5];
numv = 0;
d = [];
for k=1:15
composite=[a1(:,k) b1(:,k) c1(:,k)];
if composite(1) <= 1.5 || composite(2) >= 5 || composite(3) <= 2;
continue;
end
numv = numv + 1;
d(:,numv)=sqrt(sum((composite-origin).^2));
end
댓글 수: 2
Walter Roberson
2012년 2월 4일
if composite(1) >= 1.5 & composite(1) < 5 & composite(2) <= 5 & composite(3) >= 2 & composite(3) < 5.8
numv = numv + 1;
d(:,numv)=sqrt(sum((composite-origin).^2));
end
This is a different way of writing the same control: select what you do want rather than rejecting what you do not want.
When you say "end my calculation", if you mean for the entire loop over "k", then before just before the "end" of the "if", add
else
break
But take note that this will result in no work being done, as a1(1) is out of the desired range. So probably you just want to do what I have written here, do not calculate the result if the values are out of range for this k.
추가 답변 (1개)
Walter Roberson
2012년 2월 3일
a1=1:.3:5.2;
b1=3:.2:5.8;
c1=2:.3:6.2;
composite=[a1(:), b1(:) c1(:)];
Lidx_a = a1 <= 1.5;
Lidx_b = b1 >= 5;
Lidx_c = c1 <= 2;
composite((Lidx_a | Lidx_b | Lidx_c),:) = [];
nrow = size(compisite,1);
origin=[1.3 1.1 1.5];
d = sqrt( sum( (composite-repmat(origin,nrow,1)).^2, 2) );
No loop needed.
The second argument to sum, the 2, is needed to sum along rows.
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