How to store vectors with different size in a loop ?

조회 수: 7 (최근 30일)
Ole
Ole 2016년 3월 23일
댓글: dpb 2019년 4월 15일
How to store vectors with different size and how to access them. M(k) found_roots
F = @(t) cos(t)*exp(-t);
A = @(s) arrayfun(@(s)-integral(F,-10,s),s);
Z = @(t1,t2) -integral(A,t1,t2);
interval = [-5, 5];
N = 100;
start_pts = linspace(interval(1),interval(2),N);
found_roots = [];
for k = 1:10
t2 = k;
for i=1:numel(start_pts)-1
try
found_roots(end+1) = fzero(@(t1)Z(t1,t2),[start_pts(i),start_pts(i+1)]);
end
% i
end
M(k) = found_roots % vector of different length
k
end
  댓글 수: 2
Benjamin
Benjamin 2019년 4월 15일
But in every loop, if the size of the matrix (output here) changes Matlab gives error of different matrix sizes. Is there anysolution for that.
FYI: my Matlab code generates a matrix of [A] = n*2 and in every loop (for i = 1:10) n changes. I would like to store all A results in another B matrix.
dpb
dpb 2019년 4월 15일
That's what the Answer shows...use cell array instead of "regular" array...the difference is "the curlies" the {} around the subscript, not ()

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dpb
dpb 2016년 3월 23일
Use cell array instead; the curly brackets...
M{k} = found_roots;
  댓글 수: 2
Ole
Ole 2016년 3월 25일
편집: Ole 2016년 3월 25일
Thanks This works but now how to plot them .
dpb
dpb 2016년 3월 25일
"them" can be plotted, sure, but against what?

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