Three Loops with summation

Greeting,

I have matrix Z(30,70) and it repeated for 40 times each time there will be new value for each cell. This means for example Z(1,1) will have 40 different values. And the same for all cells in the matrix. My question how I can sum all 40 Z(1,1) for all values. I want to done this for each cell and save the result in matrix K(30,70)

Do I need to do three loops to accomplish that or there is another ways to do it.

Thank you in advance for all ideas.

Regards

[Walter Roberson]

This sounds like the same question as your earlier http://uk.mathworks.com/matlabcentral/answers/250696-summation-of-valuse-in-nested-loops

Answer 1

[Walter Roberson]

If you have a cell array Z and you want sum each of the entries, then

cellfun(@sum, Z)

if you are expecting a 30 x 70 numeric array as output, and otherwise

cellfun(@sum, Z, 'Uniform', 0)

if you are expecting a 30 x 70 cell array as output.

[Ali Kareem]

Hello,

Thank you for your reply. Please I do not think my question was clear. Below what I want to do

 for L=1:10                 
for i=1:20

    for j=1:100              

        r=(Xc+Y)^(1/2);
        VC=VCo*(1-(exp(-(r))));
        Uf(i,j)=(((VC-Yc))/((pi)*(r)));
        Vf(i,j)=((VC*r)*(Xc))/((2*pi));
        Uft(i,j)=Uft(i,j)+Uf(i,j);
        Vft(i,j)=Vft(i,j)+Vf(i,j);
        Ufz(i,j)=(U-Uft(i,j))/U;

    end;  
end;
end;

I Want to have summation of Uft and Vft. so for the entire loops (i,j) I will get the first matrix (20,100) then after that for L loop I will get the other matrices. I want Uft(1,1) to add to the Uft(1,1) from old matrix until end of loop L (this mean for ten times)

this scenario for for new A(1,2)=old A(1,2) and so on

[Walter Roberson]

   for L=1:10                 
  for i=1:20

      for j=1:100              

          r=(Xc+Y)^(1/2);
          VC=VCo*(1-(exp(-(r))));
          Uf(i,j)=(((VC-Yc))/((pi)*(r)));
          Vf(i,j)=((VC*r)*(Xc))/((2*pi));
          Uft(i,j,L)=Uft(i,j,L)+Uf(i,j);
          Vft(i,j,L)=Vft(i,j,L)+Vf(i,j);
          Ufz(i,j)=(U-Uft(i,j))/U;

      end;  
  end;
  end;

Now afterwards you can use

sum(Utf,3)
sum(Vtf,3)

Answer 2

[Matt J]

You should be keeping your Z data as a 3D array of dimension 30x70x40. Then, it's as simple as

    K=sum(Z,3);

Example,

    >> Z=rand(30,70,40); K=sum(Z,3); whos K Z

      Name       Size                Bytes  Class     Attributes

      K         30x70                16800  double              
      Z         30x70x40            672000  double

[Ali Kareem]

Hello,

Thank you for your reply.

for L=1:10                 
for i=1:20

    for j=1:100              

        r=(Xc+Y)^(1/2);
        VC=VCo*(1-(exp(-(r))));
        Uf(i,j,L)=(((VC-Yc))/((pi)*(r)));
        Uft= sum(Uf,3)/U

    end;  
end;
end;

I think my equation for sum is incorrect because I got wrong numbers

Regards