Matlab 2015a: figure() error
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以下のコードでエラーが出ます。理由を教えてください。環境はR2015aです。
fnum=-1;
fnum(fnum<1)=1;
figure(fnum);
---------------------
エラー: figure
簡易引数ハンドルが無効です
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Image Analyst
2015년 10월 23일
What's the error? Please paste all the red text. You will get more answers if you post this in English. Why are you doing that anyway? fnum<1 is just true, which evaluates to 1. So then you're doing fnum(1) = 1, followed by figure(1). So why not just do figure(1) in the first place?
답변 (1개)
Sudhanshu Bhatt
2015년 10월 29일
Hi Ryusuke,
Can you please explain more about the workflow you are trying to achieve? What is the error message you are receiving?
One possible reason for the error could be that you are passing "fnum" to FIGURE. If you want the value inside "fnum" to be passed to the FIGURE you can do something like this:
figHandle = figure(fnum(1));
Hope this helps.
Thanks
Sudhanshu Bhatt
댓글 수: 1
Walter Roberson
2015년 10월 29일
fnum in the shown code is a scalar. There is no difference, in this situation, between coding figure(fnum) and figure(fnum(1))
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