find '1' in an array
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hi ı wanna ask question about find a 1's number in array. for example the array should be like that 1 1 1 0 1 0 1 1 1 0 1 0 1 1 1 1 and ı only want to find a group of 1's. In array 0 1 0 or 1 0 1 or 0 0 0 1 0 something like that is an error in array. How can we do that. thanks
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Jan
2015년 10월 1일
What is the desired output for the given data? How should these "errors" be treated?
답변 (5개)
Guillaume
2015년 10월 1일
If you mean you want to find the start of the sequences of at least two consecutive 1, then it's simple using diff. You'll find the start of a sequence when the diff with the previous value is 1 (transition from 0 to 1), and you'll know it's followed by a 1 when the diff with the next value is 0, so:
A = [1 1 1 0 1 0 1 1 1 0 1 0 1 1 1 1]
startseq1 = find(A & diff([0 A]) == 1 & diff([A 0]) == 0)
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Guillaume
2015년 10월 1일
I have no idea what you mean. The code I've written work:
>>A = [1 1 1 0 1 0 1 1 1 0 1 0 1 1 1 1];
>>startseq1 = find(A & diff([0 A]) == 1 & diff([A 0]) == 0)
startseq1 =
1 7 13
>>endseq1 = find(A & diff([A 0]) == -1 & diff([0 A]) == 0)
endseq1 =
3 9 16
>>sequences = arrayfun(@(s,e) A(s:e), startseq1, endseq1, 'UniformOutput', false);
>>celldisp(sequences)
sequences{1} =
1 1 1
sequences{2} =
1 1 1
sequences{3} =
1 1 1 1
Thorsten
2015년 10월 1일
It is not entirely clear what you want to achieve; if you just want to get rid of the 0's, use
x = [1 1 1 0 1 0 1 1 1 0 1 0 1 1 1 1];
y = x(x==1);
Jan
2015년 10월 1일
data = [1 1 1 0 1 0 1 1 1 0 1 0 1 1 1 1];
[b, n] = RunLength(data);
result = sum(b == 1 & n > 1);
If the data are small (e.g. just some kB), or you do not have a compiler installed already, use RunLength_M instead from the same submission.
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