How to plot a graph that consist all quadrant ?
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이전 댓글 표시
x = -100:10:100;
y1 = 0.8*x; %L(x)
y2 = (-27/97750)*x.^3+(4/5)*x; %g(x)
y3 = (-81/9775)*x + (1726/1955)*x -(108/391); %q(x)
y4 = (27/97750)*x.^3 + (-162/1955)*x.^2 +6.6864*x -116.2103; %h(x)
y5 = -1.6*x + 120; %L2(x)
y6 = -0.012*x.^2 + 0.8*x; %f(x)
hold on;
plot(x,y1,'-r')
plot(x,y2,'-g')
plot(x,y3,'-b')
plot(x,y4,'-m')
plot(x,y5,'-y')
plot(x,y6,'-k')
legend('L(X)','g(x)','q(x)','h(x)','L2(x)','f(x)','location','northeast')
xlabel('x-axis')
ylabel('y-axis')
This is my script file, but the matlab only show the 1st and 4th quadrant of the graph!
I need all the quadrant include 2nd and 3rd in order to show the intercept of each graph.
댓글 수: 0
답변 (1개)
Walter Roberson
2015년 8월 22일
That code does show all the quadrants. It shows x from -100 to +100 and y from -2000 to +500. 6 lines are plotted. The yellow (L plot) might be difficult to see against the background, and the q and h plots are nearly on top of each other so it can be difficult to tell the lines apart.
You might want to move the legend to southeast instead of northeast.
댓글 수: 3
Walter Roberson
2015년 8월 24일
Use 'southoutside' for the location.
Ashish Kulkarni
2021년 9월 6일
Change your command to
legend('L(X)','g(x)','q(x)','h(x)','L2(x)','f(x)', 'location','southoutside','Orientation','horizontal')
and you'll get the legends horizontally
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