confused abt z and z(-1) in matlab
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Lets suppose i am having one transfer function as
H(z)= 1-2z/(1+3z)
and the other is
G(z) = 1-2z(-1)/ [1+3z(-1)] //Now inverse is used
If i want to take the transfer fucntion in matlab for further pole zero map, how i will tell matlab that it is z in my TF or z(-1)
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Walter Roberson
2011년 11월 13일
Is that really z multiplied by negative one? Or is it z raised to the power of negative 1, z^(-1), which is 1/z ?
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Naz
2011년 11월 13일
You can take your H(z) and divide by z. So you will have: z^(-1)-2 / z^(-1)+3. Now you can create two vectors containing zeros and poles:
B=[-2 1];
A=[3 1];
zplane(B,A)
If you have function with (all) negative powers, than the last coefficient is for the most negative power and the first coeff is a constant. In case of all positive coeff. you just inverse the order (constant is last).
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