I'm trying to graph data from an html file and I'm unsure how to load and graph it.

Question

Brendan 2023년 10월 16일

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https://kr.mathworks.com/matlabcentral/answers/2034354-i-m-trying-to-graph-data-from-an-html-file-and-i-m-unsure-how-to-load-and-graph-it

답변: Voss 2023년 10월 16일

this is the data https://coyote.eece.maine.edu/ece101/hw/umhab-137-iridium.html

im trying to graph time on the x axis and rise rate on the y

meaning (current alt-start alt)/(current time-start time)

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Answer 1

Voss 2023년 10월 16일

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링크

이 답변에 대한 바로 가기 링크

https://kr.mathworks.com/matlabcentral/answers/2034354-i-m-trying-to-graph-data-from-an-html-file-and-i-m-unsure-how-to-load-and-graph-it#answer_1334404

MATLAB Online에서 열기

url = "https://coyote.eece.maine.edu/ece101/hw/umhab-137-iridium.html";

T = readtable(url);

head(T)

IMEI Time-UTC Date Latitude Longitude Alt-m Alt-ft V_Vel-m/s V_Vel-ft/s __________ ________ ___________ ________ _________ _______ _______ _________ __________ 3.0053e+14 17:36:23 14-Oct-2023 40.734 -116.81 "2,037" "6,683" 0 0 3.0053e+14 17:36:23 14-Oct-2023 40.734 -116.81 "2,037" "6,683" 0 0 3.0053e+14 17:36:13 14-Oct-2023 40.734 -116.81 "2,037" "6,683" 0 0 3.0053e+14 17:36:13 14-Oct-2023 40.734 -116.81 "2,037" "6,683" 0 0 3.0053e+14 17:36:05 14-Oct-2023 40.734 -116.81 "2,038" "6,685" 0 0 3.0053e+14 17:36:05 14-Oct-2023 40.734 -116.81 "2,038" "6,685" 0 0 3.0053e+14 17:35:57 14-Oct-2023 40.734 -116.81 "2,038" "6,685" 0 0 3.0053e+14 17:35:57 14-Oct-2023 40.734 -116.81 "2,038" "6,685" 0 0

tail(T)

IMEI Time-UTC Date Latitude Longitude Alt-m Alt-ft V_Vel-m/s V_Vel-ft/s __________ ________ ___________ ________ _________ _______ _______ _________ __________ 3.0053e+14 05:34:58 14-Oct-2023 40.969 -117.74 "1,307" "4,289" 0 1 3.0053e+14 05:34:58 14-Oct-2023 40.969 -117.74 "1,307" "4,289" 0 1 3.0053e+14 05:34:27 14-Oct-2023 40.969 -117.74 "1,301" "4,267" 0 -2 3.0053e+14 05:34:27 14-Oct-2023 40.969 -117.74 "1,301" "4,267" 0 -2 3.0053e+14 05:32:11 14-Oct-2023 40.969 -117.74 "1,308" "4,290" 0 0 3.0053e+14 05:32:11 14-Oct-2023 40.969 -117.74 "1,308" "4,290" 0 0 3.0053e+14 05:31:46 14-Oct-2023 40.969 -117.74 "1,312" "4,304" 0 0 3.0053e+14 05:31:46 14-Oct-2023 40.969 -117.74 "1,312" "4,304" 0 0

alt = str2double(T.("Alt-m"));

time = T.("Time-UTC");

rise_rate = (alt-alt(end))./seconds(time-time(end)); % m/s

plot(time,rise_rate)