How do I alter the curve of my plot

% Set variables: g is gravity, v is velocity, i_h is initial height, h_f is final height

g = 9.81;

v = 85;

i_h = 0:0.25:95;

h_f = 0

% Equations: t being time and d being distance

t = sqrt(2*i_h\g);

d = (85*sqrt(2*i_h/g));

figure;

plot(d,i_h)

title 'i_h'

ylabel ('Height (m)')

xlabel ('Distance (m)')

grid on

How do I get my graph to start at coordinates 0, 95 and end at coordinates, 374.077, 0?

Answer 1

[Sam Chak]

g = 9.81;
v = 85;
i_h = 0:0.25:95;
h_f = 0;
% Equations: t being time and d being distance 
t = sqrt(2*i_h\g);
d = (85*sqrt(2*i_h/g));
figure;
plot(d, i_h(end)-i_h, 'linewidth', 2)
title 'i_h'
ylabel ('Height (m)')
xlabel ('Distance (m)')
grid on

[Thomas]

Could you explain this line of code: 'i_h(end)-i_h, 'linewidth', 2)'?

[Sam Chak]

Alright @Thomas, i_h(end) is 95 m, and i_h is a vector array ranging from 0 to 95. Previously, the figure was plotted with i_h as the y-axis variable and d as the x-axis variable, using the syntax "plot(d, i_h)". This resulted in the graph starting from (0, 0).

In the image you provided, it seems you want to plot the graph starting from the highest point, which naturally means you want to plot from 95 m down to 0 (ground level). One way to achieve this is by defining a new y-axis variable, like ynew = 95 - i_h, and then plotting it using "plot(d, ynew)".