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struct problem when dealing with different field types

조회 수: 6 (최근 30일)
Art
Art 2015년 4월 10일
편집: per isakson 2015년 5월 16일
I created a struct containing variables of length 'n' (numeric) in separate fields: mystruct = struct('field1',variable_1,'field2', variable_2, ...)
everything works fine and I can type mystruct.field1 and it shows the values of variable_1 from 1:n:
ans =
32 2 22 1 1 2 ...n
If I type mystruct.field1(1) I get 32. This is good.
Now I want to include a variable which is a character cell in the struct, also of length n (n cells of differing sizes). When I add this variable to the struct, all the fields change to cells (I think), and I have to type mystruct (1).field1(1) to see 32. This is bad.
Is there a way to implement a cell in a struct without changing everything to cell? Or, is there a way to make a char string into something besides a cell to be stored into struct?
I tried changing the ascii chars into a binary stream and using bin2dec to turn into the dec equivalent for use in the struct, the problem is that this only works for shorter strings. If the string is too long, the decimal equivalent is too big for Matlab to handle.
Any ideas?
  댓글 수: 3
Art
Art 2015년 4월 10일
편집: per isakson 2015년 5월 16일
OK, so here is what I am doing..
I have a large loop which parses a binary file and defines variables:
for i = 1:n
variable1(i) = bin2dec(binaryfile(1:4)) %%bytes 1-4
variable2(i) = bin2dec(binaryfile(5:8))
...
variableX(i) = {char(binaryfile(30:50))}
end
%
mystruct = ('field1',variable1, ...)
most variables are a decimal representation of 4 bytes from a large data file (I merge the 4 bytes into one 32bit binary stream first, then bin2dec it). The problem is that there are a couple variables that are 20 bytes (160 bits), which is too large to change to decimal.
When I comment out the "variableX" line in the above code, I get a struct of length "1" containing variables of length "n". When I keep the "variableX" line in, I get a struct of length "n" with variables of length "n" as well.
I'd like to keep everything in decimal form as many variables will be plotted from the struct.
James Tursa
James Tursa 2015년 4월 10일
See Per's solution using the { } wrapper for the cell array of strings. E.g., for your case:
mystruct = struct('field1',variable1, ... ,'fieldX',{variableX})

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per isakson
per isakson 2015년 4월 10일
편집: per isakson 2015년 4월 10일
"implement a cell in a struct" &nbsp I'm not sure I understand.
Hint:
>> sas = struct('vec',[1:12],'string','abcdefgh','cellstr',{{'abc123','def456'}})
sas =
vec: [1 2 3 4 5 6 7 8 9 10 11 12]
string: 'abcdefgh'
cellstr: {'abc123' 'def456'}
>> sas.structure = struct('f1',1,'s1','a' )
sas =
vec: [1 2 3 4 5 6 7 8 9 10 11 12]
string: 'abcdefgh'
cellstr: {'abc123' 'def456'}
structure: [1x1 struct]
>>
  댓글 수: 9
James Tursa
James Tursa 2015년 4월 10일
편집: James Tursa 2015년 4월 10일
Well, you could find out if varname is a cell array and then take appropriate steps as you see fit. E.g.,
var_is_cell = eval(['iscell(' varname ')']);
if( var_is_cell )
varadd = ['{' varname '}'];
else
varadd = varname;
end
struct_construct = strcat(struct_construct,sprintf('''%s'',%s,',varname,varadd));
Or you could put in code to actually change the variable in question to a scalar cell array:
if( var_is_cell )
eval([varname '={' varname '}']);
end
But this is getting ugly, isn't it? Are you sure you want to go down this route of generating struct's with fieldnames that are defined from strings in real-time? How are you planning on dealing with this downstream in your code? More sprintf's and eval's? This is going to be a real headache down the road for you to manage the code for readability and maintainability.
Art
Art 2015년 4월 29일
yes, maintainability may be an issue, luckily I do know beforehand which variables will be what types. Thanks for all the input

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