how can i get the minimum total from the three total since it only display the final value of the total.

hello.i want to get the minimum total from the three total.but it only display the final total(1x1)=29 not the total i expect which is total(3x1)=[26;27;29].

Below is my code.

if true
  % code
end  a = [4;1;9];
  b = [3;1;4;6;7];

    for i=1:1:3
        total=0;
        c=((b(i:i+2)-a).^2);
        disp(c);

        for i=1:1:3
            total = c(i,1)+ total;
        end
        disp(total);
    end

please help me to solve this.Thanks in advance.

Answer 1

[Brendan Hamm]

You are changing your looping variable inside the loop. I think you want:

a = [4;1;9];
b = [3;1;4;6;7];
c = zeros(3,3); % Pre-allocate storage

for i = 1:1:3
    c(:,i) = ((b(i:i+2)-a).^2);
end % End here
disp(c);

total = 0;
for i = 1:1:3
    total = c(:,1) + total;
end

disp(total);

[aziz syahirah]

thank you for the answer but it give me an error

??? In an assignment A(I) = B, the number of elements in B and I must be the same.

Error in ==> m1 at 32 c(i) = ((b(i:i+2)-a).^2);

[Brendan Hamm]

Edited the answer. I apologize, I didn't have access to MATLAB before.