How can I create a for loop when the range is changing
조회 수: 3 (최근 30일)
이전 댓글 표시
Hello,
I have a code as following. Code works as intended it sorts the elements as I want. After that I want to print the first element of sorted array and the corresponding distance. Actually each distance represents a song but I didn't write their names therefore I use the index of distance. My problem is there are some duplicates is sorted array. So, when I run the code if there are two times 0.5 distance it prints the same line 2 times. I somehow need to delete all coppies of sorted(i) without changing the lenght of it. If I just delete it since i goes until 19 sorted(i) will give error of index out of range. How can I solve this problem?
clc;clear;
Crescendo = [0 1 0 1 0 0 1 1 0 0 1 1 0 0 1 1 0 1 0 0]';
Descrescendo = [1 1 1 1 1 1 1 1 1 0 1 1 1 1 0 0 1 1 0 0]';
Staccato = [0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 1 1 0 0 0]';
Portamento = [0 0 0 1 0 1 1 1 0 0 0 1 1 0 0 1 0 1 0 0]';
Tempo = [1 1 1 0 1 0 1 0 0 1 1 1 1 0 1 0 0 0 1 1]';
Intervals = [0 1 1 1 1 1 0 1 1 0 0 0 1 0 0 1 1 1 1 1]';
M = [Crescendo Descrescendo Staccato Portamento Tempo Intervals];
S = M*M';
[U,W,V] = svds(S,2);
%labels = cellstr(num2str([1 : length(U)]'));
%plot(U(: ,1),U(: ,2),'rx');
%text(U(: ,1),U(: ,2), labels)
distance = zeros(19,1);
for i=2:20
distance(i-1,1) = dot(U(1,:),U(i,:))/(norm(U(1,:))*norm(U(i,:)));
end
sorted = sort(distance,"descend");
for i=1:19
index = find(distance==sorted(i));
[m,n] = size(index);
if m == 3
fprintf("Song number %d, %d and %d are %f close to song 1\n",index,sorted(i))
elseif m == 2
fprintf("Song number %d and %d are %f close to song 1\n",index,sorted(i))
else
fprintf("Song number %d is %f close to song 1\n",index,sorted(i))
end
end
댓글 수: 0
답변 (1개)
Matt J
2022년 12월 24일
Crescendo = [0 1 0 1 0 0 1 1 0 0 1 1 0 0 1 1 0 1 0 0]';
Descrescendo = [1 1 1 1 1 1 1 1 1 0 1 1 1 1 0 0 1 1 0 0]';
Staccato = [0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 1 1 0 0 0]';
Portamento = [0 0 0 1 0 1 1 1 0 0 0 1 1 0 0 1 0 1 0 0]';
Tempo = [1 1 1 0 1 0 1 0 0 1 1 1 1 0 1 0 0 0 1 1]';
Intervals = [0 1 1 1 1 1 0 1 1 0 0 0 1 0 0 1 1 1 1 1]';
M = [Crescendo Descrescendo Staccato Portamento Tempo Intervals];
S = M*M';
[U,W,V] = svds(S,2);
U=normalize(U,2,'n');
distance = U(2:19,:)*U(1,:).';
sorted=flip(unique(distance));
for i=1:numel(sorted)
index = find(distance==sorted(i));
m=numel(index);
if m == 3
fprintf("Song number %d, %d and %d are %f close to song 1\n",index,sorted(i))
elseif m == 2
fprintf("Song number %d and %d are %f close to song 1\n",index,sorted(i))
else
fprintf("Song number %d is %f close to song 1\n",index,sorted(i))
end
end
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Matrix Indexing에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!