WHy do I get "ans = 1" in the Command Window?
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In running a program I have written using the pdepe function, and sometime during the function call:
soln=pdepe(m,@solnpde,@solnic,@solnbc,r,t,options);
I get a lot of "ans = 1" scrolling in the Command Window. The solution pdepe returns appears to be correct.
What does this mean? How can it be suppressed?
Thanks, Doug
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답변 (4개)
Fangjun Jiang
2011년 10월 7일
Check all of the three functions solnpde, solnic and solnbc. There must be a line somewhere that doesn't have the ; at the end, thus the output is shown in the Command Window.
Run the following line and then run your program. Hope it can help you find where the ans=1 comes from.
echo on all
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Fangjun Jiang
2011년 10월 7일
Yes. You can see from the below example how 'ans = 1' appear. You probably have some debugging line accidentally left in the code. Use break point to narrow down while file and then trace down to the line. You have to follow all the functions that are called.
>> 2-1;
>> 2-1
ans =
1
>> a=1;
>> a=1
a =
1
Walter Roberson
2011년 10월 7일
Try
dbstop in disp
and then run. When it stops in the debugger, look at the code. There will not be any explicit call to disp() in the situation you are seeing, but disp() is what is called internally.
Though it might be "display" instead of "disp"... I have not had reason to figure out which of the two names is used in which circumstances.
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Daniel Shub
2011년 10월 7일
I had thought that a solution to this question would have been to overload display/disp to call dbstack so I was looking at what is being called. It turns out that display is super special and cannot be "overloaded". If you write a function called display.m and put it in your current directory, MATLAB ignores it.
Daniel Shub
2011년 10월 7일
Do you have any eval statements in your code. It is possible that all your "lines" are terminated with a semicolon, but that the eval is not.
x = 1;
eval('x');
compared to
eval('x;');
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Jan
2011년 10월 7일
There is also a difference between these two calls:
fprintf(1, '\n'); % Print a line break in the command window
fprintf('1', '\n'); % Print a '1' to the command window
The 2nd ignored the '\n' and is most likely not intented, but a typo.
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