# matrix is singular to working precision , Contour not rendered for non-finite ZData

조회 수: 2 (최근 30일)
idan 2022년 7월 21일
답변: Shivam 2023년 10월 5일
Hello,
I have read through all the trouble shooting advice on this website for the above error. I have attached my code, and I am not sure what I am doing that is causing this error.
Could somebody guide me what I am doing wornk?
Thanks.
function [] = Plot3D(cellArray,charArray)
x = linspace(-15,15,100);
y = linspace(-15,15,100);
[xx,yy] = meshgrid(x,y);
z = (sin(sqrt(xx .^2 + yy .^2)))/(sqrt(xx .^2 +yy .^2));
switch charArray
case 'surfc'
surfc(xx,yy,z);
xlabel(cellArray{2});
ylabel(cellArray{4});
zlabel(cellArray{6});
case 'surf'
surf(xx,yy,z);
grid on;
title("This is the surf:");
case 'contour'
grid on;
contour(xx,yy,z,'ShowText','on');
axis([-15 15 -15 15 -15 15]);
otherwise
subplot(2,2,1);
surfc(xx,yy,z);
subplot(2,2,2);
surf(xx,yy,z);
subplot(2,2,[3,4]);
contour(xx,yy,z);
end
##### 댓글 수: 3이전 댓글 1개 표시이전 댓글 1개 숨기기
Abderrahim. B 2022년 7월 21일
Hi!
Please, share the error. And if possible, share cellArray and charArray.
Thanks
idan 2022년 7월 21일
Hello,
This is the error:
Warning: Matrix is singular to working precision.
Warning: Contour not rendered for non-finite ZData
Warning: Matrix is singular to working precision.
Warning: Matrix is singular to working precision.
Warning: Contour not rendered for non-finite ZData
Warning: Matrix is singular to working precision.
Warning: Contour not rendered for non-finite ZData
Warning: Contour not rendered for non-finite ZData
And this is the code I am trying to run:
load('cellArray.ma'); % something that I load from my computer to see if the function working.
figure('Name', 'surfc')
Plot3D(cellArray, 'surfc')
figure('Name', 'surf')
Plot3D(cellArray, 'surf')
figure('Name', 'contour')
Plot3D(cellArray, 'contour')
figure('Name', 'abc')
Plot3D(cellArray, 'abc')
Thanks.

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### 답변 (1개)

Shivam 2023년 10월 5일
Hi @idan,
As per my understanding, you are trying to make different figures using surfc, surf, contour, and plot3, where the provided code's execution is leading to warnings.
You can overcome the warnings by utilizing element-wise division instead of regular division when calculating the variable 'z.' The updated code line would look as follows:
z = (sin(sqrt(xx .^2 + yy .^2)))./(sqrt(xx .^2 +yy .^2));
I hope it helps.

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