How to find the nearest matrix between two matrices?

조회 수: 1(최근 30일)
MP
MP 2022년 7월 18일
댓글: MP 2022년 7월 19일
Find the nearest row matching between matrix.
I have a matrix
A = [2013 03 17 1 6 0]; % 1x6 double
I have another matrix
B = [2013 3 17 0 5 1.012; 2013 3 17 1 6 20.47]; % 4x6 double
I want to find the index of the nearest matrix A in B.
Can anyone please help?
Any help will be greatly appriciated.

채택된 답변

Rik
Rik 2022년 7월 18일
Convert each row to a date format (either datetime or datenum).
After that you can subtract one from the other, use abs and min to find the smallest difference. Use the second output of min to find the index of the smallest difference.
  댓글 수: 1
Stephen23
Stephen23 2022년 7월 18일
편집: Stephen23 2022년 7월 18일
A = [2013,3,17,1,6,0]; % 1x6 double
B = [2013,3,17,0,5,1.012; 2013,3,17,1,6,20.47]; % 4x6 double
The best way of storing timestamps is as DATETIME objects:
Adt = datetime(A)
Adt = datetime
17-Mar-2013 01:06:00
Bdt = datetime(B)
Bdt = 2×1 datetime array
17-Mar-2013 00:05:01 17-Mar-2013 01:06:20
Then just use ABS and MIN exactly as Rik recommended:
[~,idx] = min(abs(Adt-Bdt))
idx = 2
Bdt(idx)
ans = datetime
17-Mar-2013 01:06:20

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추가 답변(1개)

Abderrahim. B
Abderrahim. B 2022년 7월 18일
편집: Abderrahim. B 2022년 7월 18일
clear
A = [2013,3,17,1,6,0]; % 1x6 double
B = [2013,3,17,0,5,1.012; 2013,3,17,1,6,20.47]; % 4x6 double
A = datetime(A) ;
B = datetime(B) ;
minSize_B = max(size(B)) ;
nearestAB = [] ;
for ii = 1:minSize_B
nearestAB = [nearestAB abs(A - B(ii))] ;
end
[~, nearestB_indx] = min(nearestAB) % Means, the 4th row in B
nearestB_indx = 2
nearestB = B(nearestB_indx)
nearestB = datetime
17-Mar-2013 01:06:20
  댓글 수: 5
MP
MP 2022년 7월 19일
Yes, @Rik, thanks for helping. I was trying how to implement it but @Stephen23's comment did a great help.

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