square wave not "limited"

조회 수: 3 (최근 30일)
Federico Paolucci
Federico Paolucci 2022년 6월 30일
답변: Jon 2022년 6월 30일
hi, I produced this square wave signal, but as you can see the square peaks have no upper limit. how can i solve?
x=0.03*square(f*t,duty)
in reality I seem to see that the graph is the other way around

채택된 답변

Jon
Jon 2022년 6월 30일
You probably are not correctly specifiying the duty cycle. If you want the square wave to be "on" half the time you should set duty = 50, also note that the first argument to square is in radians, so each cycle is 2*pi radians. You have to scale your input accordingly.

추가 답변 (1개)

Sam Chak
Sam Chak 2022년 6월 30일
Doesn't seem to have any issue.
t = linspace(0, 3*pi, 3001)';
f = 2;
duty = 50;
x = 0.03*square(f*t, duty);
plot(t/pi, x, t/pi, 0.03*sin(2*t))
grid on
ylim([-0.05 0.05])

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