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to find zero crossing rate for a signal

조회 수: 1 (최근 30일)
Amit
Amit 2015년 1월 21일
댓글: Ced 2015년 1월 21일
hello, i have following data and i want to find ZERO CROSSING RATE for the following:
A=[34.157226 -35.159323 35.459952 -34.057017 -32.704186 -33.180182 -32.22819 -32.403557 -32.303347 -32.253243 -32.578924 -32.253243 -32.428609 -31.777247 -31.927561 -32.403557 -31.60188 32.12798 -31.952613 31.60188 -31.351355 -32.153033 31.201041 -30.324206 -30.975569 -30.975569 -30.900412 -31.877456 -31.226093 -32.22819 -32.353452 -32.378505 -32.203138 -32.102928 -32.729238 -33.606073 -32.654081 -33.68123 -34.307541 35.259533 35.284585 35.660372 35.635319 35.33469 6.186472 -36.912993 -38.115509 -38.566452 -38.566452 -38.741819 -39.593601 -40.971484 -41.422428 -42.825363 -42.825363 -42.624944 -43.351464 44.328508 44.278403 -44.278403 45.480919 46.232492 -46.883855 46.984064 -47.009117 -48.28679 ]
would anyone help me out???

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Ced
Ced 2015년 1월 21일
Sure... it's 0, because your signal is always negative.
  댓글 수: 2
Amit
Amit 2015년 1월 21일
but let me change the question sorry.please see it now.
Ced
Ced 2015년 1월 21일
Do you know the formula for the zero crossing rate?
Try to fill in this function:
function rate = zero_crossing_rate(signal)
signal = signal(:);
T = length(signal);
% % Enter the function from wikipedia here
rate = ...
end
Hints: The simplest way would be to create a for loop and check the (s_t*s_{t-1}<0) property.

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