Solution of equation of difference

조회 수: 1(최근 30일)
Nick Vasilakis
Nick Vasilakis 2022년 1월 26일
편집: Yash Srivastava 2022년 2월 2일
Hello! So I'm trying to solve this equation:
for A>0 and being my main variable
Initial value of y(-1)=3 and for N=30 loops
This is the code I've managed to write:
function res = my_matlab_function(A,N)
%definition of y(-1)=3
y_1=3;
% calculating the first value of y(0)
y(0)=0.5*y_1+(0.5*(A^2))/(y_1);
%calculating the rest
for i=1:N-1
y(i)=0.5*(y(i-1)+((A^2)/y(i-1)));
result = my_matlab_function(A,N);
disp(['A= ' num2str(A) 'Result=' num2str(result)])
end
but MATLAB returns to me the followed error:
Not enough input arguments.
Error in my_matlab_function (line 8)
y(0)=0.5*y_1+(0.5*(A^2))/(y_1);

답변(1개)

Yash Srivastava
Yash Srivastava 2022년 2월 2일
편집: Yash Srivastava 2022년 2월 2일
Hello Nick,
I am assuming that you are trying to run the script file directly by pressing the ‘Run’ button or executing the file from command window. For a file with function to run properly, you need to pass arguments.
You may refer the below documentation to pass arguments to functions with the help of ‘Run’ button:
You may also refer the below link to pass arguments to functions using command window:
Also, Array indexing starts from 1 in MATLAB. You may adjust your index values accordingly.

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