Change certain values in a matrix

Hi all I jhave a matrix A

A=[1 1 0 0 1 1 1 0; 0 0 1 1 1 1 0 0; 1 1 0 0 1 1 0 1; 1 1 1 1 1 1 1 1; 1 1 1 1 1 1 1 1]

I would like to "correct" its columns like this:

when I have a column where the sequence "0 1 0" appears I want to be changed to "0 0 0"

AND

when I have a column where the sequence "1 0 1" appears I want to be changed to "1 1 1"

So I have finaly the matrix B

B=[1 1 0 0 1 1 1 0; 1 1 0 0 1 1 0 0; 1 1 0 0 1 1 0 1; 1 1 1 1 1 1 1 1; 1 1 1 1 1 1 1 1]

I would like to use it for a larger matrix under this concept.

Do you know how to do it?

thanks in advance!

[Torsten]

What if the matrix has a column [1; 0; 1; 0] ?

Does if become [1 ;1; 1 ;0] or [1 ;0 ;0 ;0] ?

[Nikolas Spiliopoulos]

I would say [1;0;0;0]

thanks!

[Torsten]

I would say you have to define another rule.

[Nikolas Spiliopoulos]

ok thanks!

Answer 1

[Nihal]

Hi Nikolas,

I have understood that you are looking to replace specific patterns in a column vector. To perform the action you can try the below code which will yeild the desired result:

A=[1 1 0 0 1 1 1 0; 0 0 1 1 1 1 0 0; 1 1 0 0 1 1 0 1; 1 1 1 1 1 1 1 1; 1 1 1 1 1 1 1 1];
B=[1 1 0 0 1 1 1 0; 1 1 0 0 1 1 0 0; 1 1 0 0 1 1 0 1; 1 1 1 1 1 1 1 1; 1 1 1 1 1 1 1 1];

X=A;

% row vector format 
pattern1 = [0 1 0]; 
pattern2 = [1 0 1 1];

X = applyFilter(A,pattern1,[0 0 0]);
X = applyFilter(X,pattern2,[1 1 1 1]);

isequal(X,B)  % Check if X is equal to B
X  % Display the corrected matrix X
B  % Display the desired matrix B


function X = applyFilter(A,pattern,replaceWith)
X=A;
patternSize = size(pattern,2);
for row = 1:size(A,1)- patternSize
    for col = 1:size(A, 2)
        isequal(A(row:row+patternSize-1, col), pattern' );  % Check if the pattern matches the current submatrix
        if isequal(A(row:row+patternSize-1, col), pattern' )
            X(row:row+patternSize-1, col)= replaceWith';  % Replace the submatrix with the specified values
        end
    end
end
end

Feel free to modify the code according your usecase. I hope it helped in resolving your issue.