Can anyone pls help me with the following code;

choice=input('enter a no.to be recognized:no.1 for trained words,no.2 for not trained words:');
if choice==1)
    [pathname,filename]=uigetfile('*.wav','Select a wave file');
    current=strcat(filename,pathname);
    input=wavread(current);
    disp('y');
else
    disp('n');
end

when i give input as 1,then it must enter into 'if'loop or else it should enter into else condition.

Answer 1

[Harry]

Your code is mostly correct, just remove the ")" at the end of your 'if' statement:

if choice==1

[Shenbagalakshmi Veliah]

Thank u very much for ur reply Harry.But my problem is that for the first time if i entered '1'it enters the loop and it gets displayed as 'y',for second time if i run the same program it does not ask me the input.so i think the execution itself is stopped for only once.can u pls help me with this problem.

[Harry]

Ah yes, your problem is that you have named a variable "input"... but you also need to use a function called "input".

Therefore, when you create the variable input=wavread(current), this means you can't call the function choice=input(...) any more.

The easy solution is to rename your variable "input". For example, try this:

choice=input('enter a no.to be recognized:no.1 for trained words,no.2 for not trained words:');
if choice==1
    [pathname,filename]=uigetfile('*.wav','Select a wave file');
    current=strcat(filename,pathname);
    wave=wavread(current);
    disp('y');
else
    disp('n');
end

In the future, you should always clear all your variables at the start of your code, using:

clear all;

This will prevent many problems like this from happening.