Error using for loop to delete empty cell array elements

I want to completely delete the null elements of routes_log cell array. I use the following code.

     temp_routes_log=routes_log
     for i=1:numel(temp_routes_log)
         if (isempty(temp_routes_log{i})==1)
             routes_log(i)=[]
         end
     end
     %routes_log can be like  {0×0 double}  {1×3 double} and I want to 
     % completely remove the {0×0 double} and make routes_log as just {1×3 double}

But I get error in the case when (for e.g.) 5th entry is null in temp_routes_log but as I am deleting the routes_log elements, the routes_log is no more containing 5 elements and it throws an error at

routes_log(i)=[]

I also tried storing the indices i and then deleting those routes_log elements directly but I some other error was coming. Please guide on how can I achieve the deletion.

Answer 1

[per isakson]

Replace

for i=1:numel(temp_routes_log)

by

for i = numel(temp_routes_log) : -1 : 1  % loop from last to first element

OR if routes_log is large and speed becomes an issue

to_be_deleted = false(1,numel(routes_log))
for i=1:numel(temp_routes_log)
    if isempty(temp_routes_log{i})
        to_be_deleted(i) = true;
    end
end
routes_log(to_be_deleted) = [];

Caveat: not tested

[Jaya]

For now, routes_log is not so big. So, I used the first solution. Thanks.

Update: The second method works too! I later encountered large sized routes_log & revisited this solution to try the second way.