Hello everyone!
I want to create a loop similar to:
t=1:24:300
BUT I don't want the loop to skip 24 values after every run-through. After each run-through I want to tell the loop exactly how many values it should skip.
For example: The first run-through should be from 1:24, the second should be from 25:30, the third should be from 31:50.... and the last one from 277:300.
Is this possible in matlab?

댓글 수: 2

José-Luis
José-Luis 2014년 9월 28일
편집: José-Luis 2014년 9월 28일
Do you know the values beforehand or will they be calculated inside the loop? Also, I don't really understand what you mean by 25:30, 31:50, etc...
I just found a solution :)
I can do
t=1:s:300
then I can calculate the number of steps to skip within the loop :)

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 채택된 답변

Star Strider
Star Strider 2014년 9월 28일

0 개 추천

This seems to do what you want:
X = linspace(0, 10, 300); % Create Data Vector
t = [0 24 30 50 276 300]; % Partition Index Vector
for k1 = 1:length(t)-1
Y{k1} = X(t(k1)+1:t(k1+1));
end
The cell array ‘Y’ has your partitioned sections from vector ‘X’. Create ‘t’ to be whatever values you want. I used the numbers you defined in your Question in this example.

댓글 수: 1

MC3105
MC3105 2014년 9월 28일
편집: MC3105 2014년 9월 28일
unfortunately i don't know beforehand how my intervals will look like..
but I just found my solution: it's possible to do t=1:s:24 and then calculate the number of steps that the loop should skip before the next run-through as s within my loop :)

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추가 답변 (1개)

Marc
Marc 2014년 9월 28일

0 개 추천

It is definitely possible but your logic is not very clear. Since you are choosing odd intervals, is there some underlying reason for 1 thru 24 followed by 25 thru 30, etc. etc.
You could use if/else-if/else or switch/case or while but we would need to have some condition met to move to the next run, and so on.

카테고리

도움말 센터 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

질문:

2014년 9월 28일

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2014년 9월 28일

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