how to convert decimal values into 8bit binary values in a 256*256 matrix.

i have taken a 256*256 image and found each of the pixel values. now i need to convert each of these pixel values into 8 bit binary sequence and display it as a 256*256 matrix. i have a problem here...i have used a for loop to compute binary sequence of each value..but only the last value is displayed...please help..the code is as follows

>>a=imread('C:\Users\a.png');

>>disp(a);

>>for i=1:256

>>for j=1:256

>>b= de2bi(a(i,j),8);

>>disp(b)

>>end

>> end

thanks in advance..

Answer 1

[Pratik Bajaria]

Its Pretty Simple. You have not made 'b' into an array. do it and its all done.

i.e. Change it to the following

a=imread('C:\Users\a.png'); disp(a); for i=1:256 for j=1:256 b(i,j,:) = de2bi(a(i,j),8); disp(b) end end

Please let me know if in case of further doubts.

Regards, Pratik

[Abirami]

thank u it worked...but im getting only one bit result for each....pls suggest any edits so that i get 8 bit sequence for each pixel value.....

[Pratik Bajaria]

I think you might have skipped the 3rd dimension. Just take this code and copy paste it. It will work. a=imread('C:\Users\a.png'); disp(a); for i=1:256 for j=1:256 b(i,j,:) = de2bi(a(i,j),8); disp(b) end end

What i assume is that you might have skipped ' b(i,j,:) ' the colon is 3rd dimension, which is why you are getting only one bit. Change it and its done.

Please let me know in case of further doubts.

Regards, Pratik

[Abirami]

This code runs but no 8 bit sequences...pls help..thanks in advance

[Pratik Bajaria]

Did you try the 3rd dimension thing? In the sense, the 8-bit sequence lies in b(i,j,:). i.e. all the 3rd dimension elements of i-th row and j-th column. so for a's i,jth pixels corresponding 8-bit sequence lies in b's i,j,:th entries. I hope i am clear now. Please let me know if it still is unclear.

Regards, Pratik

[Abirami]

Thank u so much....got the 8bit sequences...

[diwa]

Plzz tell me how can I get maximum value among all these binary values of 8 bit