steady state responce of LTI system

조회 수: 2 (최근 30일)
Muhammad
Muhammad 2021년 9월 10일
답변: Star Strider 2021년 9월 10일
clc
clear all
A=[-0.0295 0.0478 0 -9.81;-0.1777 -1.4411 120 0;0.0005 -0.033 -1.5345 0;0 0 1 0]
B=[0;-12.81;-6.59;0]
C=[0 0 0 1]
D=[0]
[num ,dem]=ss2tf(A,B,C,D)
[z,p,k]=tf2zp(num,dem)
t=linspace(0,100,100)
% i have this LTI system and i want to find out the steady state responce
% in magnitude and phase at w=0.1 rad/s
sys=tf(num,dem)
% is there is any commad that can do it in matlab as i am new in matlab so

채택된 답변

Star Strider
Star Strider 2021년 9월 10일
Try this —
A=[-0.0295 0.0478 0 -9.81;-0.1777 -1.4411 120 0;0.0005 -0.033 -1.5345 0;0 0 1 0]
A = 4×4
-0.0295 0.0478 0 -9.8100 -0.1777 -1.4411 120.0000 0 0.0005 -0.0330 -1.5345 0 0 0 1.0000 0
B=[0;-12.81;-6.59;0]
B = 4×1
0 -12.8100 -6.5900 0
C=[0 0 0 1]
C = 1×4
0 0 0 1
D=[0]
D = 0
sys = ss(A,B,C,D)
sys = A = x1 x2 x3 x4 x1 -0.0295 0.0478 0 -9.81 x2 -0.1777 -1.441 120 0 x3 0.0005 -0.033 -1.534 0 x4 0 0 1 0 B = u1 x1 0 x2 -12.81 x3 -6.59 x4 0 C = x1 x2 x3 x4 y1 0 0 0 1 D = u1 y1 0 Continuous-time state-space model.
figure
stepplot(sys)
[y,tOut] = step(sys);
yFinal = y(end)
yFinal = -4.9676
tFinal = tOut(end)
tFinal = 423.9577
S = stepinfo(sys)
S = struct with fields:
RiseTime: 2.5467 SettlingTime: 301.8693 SettlingMin: -16.4422 SettlingMax: 2.5391 Overshoot: 227.8385 Undershoot: 50.6273 Peak: 16.4422 PeakTime: 18.4329
Experiment to get different results.
.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Time and Frequency Domain Analysis에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by