# How to find particular elements of matrix?

조회 수: 2(최근 30일)
Ammy 2021년 8월 22일
댓글: Walter Roberson 2021년 8월 22일
A=reshape(1:36,6,6);
How to select the following elements of matrix
7,25,
2,14,20,32
9,27
10,28
5,17,23,35
12,30
these can be find like this
A(1,2)=7, A(1,4)=25....
But is there any generalized way which help even for large matrices.

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### 채택된 답변

Walter Roberson 2021년 8월 22일
A=reshape(1:36,6,6)
A = 6×6
1 7 13 19 25 31 2 8 14 20 26 32 3 9 15 21 27 33 4 10 16 22 28 34 5 11 17 23 29 35 6 12 18 24 30 36
targets = {
[7,25]
[2,14,20,32]
[9,27]
[10,28]
[5,17,23,35]
[12,30]
}
targets = 6×1 cell array
{[ 7 25]} {[2 14 20 32]} {[ 9 27]} {[ 10 28]} {[5 17 23 35]} {[ 12 30]}
for K = 1 : length(targets)
[~, locations{K}] = ismember(targets{K}, A(K,:));
end
celldisp(locations)
locations{1} = 2 5 locations{2} = 1 3 4 6 locations{3} = 2 5 locations{4} = 2 5 locations{5} = 1 3 4 6 locations{6} = 2 5
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Walter Roberson 2021년 8월 22일
You have two index patterns:
1. columns 2 and 5
2. columns 1, 3, 4, 6
However, it is not obvious which pattern is to be applied to which row. The longer extracts are rows 2 and 5, which happens to match the column numbers for the shorter rows, but will that always be the case?
You talk about larger matrices, but do not give us any information about how the accesses will generalize. For example are we to deduce that 2, 5 is "second and second-last" ? Are we to deduce that 1, 3, 4, 6 is "first, two middle, last", or are we to deduce that it "everything not selected by the previous pattern" ?

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