# Elegant way to know in which iteration of for I am

조회 수: 5 (최근 30일)
Inês 2014년 7월 23일
편집: per isakson 2014년 7월 24일
At the moment I have something of the sort:
n_runs=0;
N_categories=[17, 8];
for protocol_ID=[4 1 7 6]
for t=1:nTrialsPerBlock
n_runs=n_runs+1;
if n_runs > N_categories
(--code--)
end
(---code---)
end
end
What I am looking for is a way to evaluate in which protocol the first for is (meaning if it is in 4, 1, 7 or 6) and then if it is in the first two, should be n_runs > N_categories( 1 ) and if it's the second pair N_categories( 2 ).
I am trying to code it so that it determines in which protocol I am, and according to that evaluate if the number of runs is bigger than the corresponding N_categories. Note that protocol_ID could have any of the numbers (4,1,7,6) in no particular order.
I am not seeing a better way than a bunch of switches/if's. Anyone could give a hand? :)
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Inês 2014년 7월 23일
I was looking for something other than switch because the instructions on each pair would be equal here. Can a switch work if I do:
switch protocol_ID
case 1 || 4
case 6 || 7
?
per isakson 2014년 7월 23일
See the answer of dpb below.

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### 답변 (3개)

dpb 2014년 7월 23일
...Can a switch work if I do:
switch protocol_ID
case 1 || 4
case 6 || 7
Not in that exact syntax, no, but
switch protocol_ID
case {1, 4}
...
case {6, 7}
...
otherwise
...
doc switch % etc., for details...
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dpb 2014년 7월 23일
I don't follow what the end objective is from the description, but to know which iteration numerically is being evaluated you've got the indicator variable being incremented in the wrong place--
iter=0;
N_categories=[17, 8];
for protocol_ID=[4 1 7 6]
iter=iter+1;
if round(iter/2)==1
% stuff for first two
else
% second two
end
...
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Inês 2014년 7월 23일
편집: Inês 2014년 7월 23일
Yeah I didn't explain it right, sorry. The thing is protocol_ID is meant to be changed into any order, so it could also be [6, 4, 7, 1] or [4, 1] for example, depending on what the user wants. What I want is to know in which protocol_ID the loop is at the moment, to know which stuff to do. It happens that 4/1 and 6/7 should have the same instructions.
So you see, just counting iterations wouldn't work because I don't want to know how many, just what the current protocol is.

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lvn 2014년 7월 23일
편집: lvn 2014년 7월 23일
This should do it:
if (protocol_ID==1 || protocol_ID==4) && n_runs > N_categories( 1 )
..
elseif (protocol_ID==6 || protocol_ID==7) && n_runs > N_categories( 2 )
..
end

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