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You may assume that the years will only have four digits, and that the start year will be smaller than the end year.\r\n\r\nFor example:  if start=1000 and finish=1023, your output should be 1, as 1023 is the only year in that range that has four unique digits.","description_html":"\u003cp\u003eHappy 2013, everyone!  An interesting tidbit about 2013 is that it is the first year since 1987 to contain four different digits.  Write a MATLAB function that, when given a start year and an end year, will tell you how many of the years between these two values have four unique digits.  You may assume that the years will only have four digits, and that the start year will be smaller than the end year.\u003c/p\u003e\u003cp\u003eFor example:  if start=1000 and finish=1023, your output should be 1, as 1023 is the only year in that range that has four unique digits.\u003c/p\u003e","function_template":"function temp=diff_digits(start,finish)\r\n\r\ntemp=start-finish\r\n\r\nend","test_suite":"%%\r\nstart=1000; finish=1023; y_correct = 1;\r\nassert(isequal(diff_digits(start,finish),y_correct))\r\n%%\r\nstart=1000; finish=9999; y_correct = 4536;\r\nassert(isequal(diff_digits(start,finish),y_correct))\r\n%%\r\nstart=1234; finish=5678; y_correct = 2273;\r\nassert(isequal(diff_digits(start,finish),y_correct))\r\n%%\r\nassert(isequal(diff_digits(4321,6789),1210))\r\n%%\r\nassert(isequal(diff_digits(1988,2012),0))","published":true,"deleted":false,"likes_count":10,"comments_count":3,"created_by":1615,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":193,"test_suite_updated_at":"2018-05-24T11:43:36.000Z","rescore_all_solutions":true,"group_id":44,"created_at":"2013-01-02T16:17:59.000Z","updated_at":"2026-02-07T16:08:31.000Z","published_at":"2013-01-02T16:20:24.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eHappy 2013, everyone! An interesting tidbit about 2013 is that it is the first year since 1987 to contain four different digits. Write a MATLAB function that, when given a start year and an end year, will tell you how many of the years between these two values have four unique digits. You may assume that the years will only have four digits, and that the start year will be smaller than the end year.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor example: if start=1000 and finish=1023, your output should be 1, as 1023 is the only year in that range that has four unique digits.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"errors":[],"problems":[{"id":1162,"title":"Happy 2013...","description":"Happy 2013, everyone!  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You may assume that the years will only have four digits, and that the start year will be smaller than the end year.\u003c/p\u003e\u003cp\u003eFor example:  if start=1000 and finish=1023, your output should be 1, as 1023 is the only year in that range that has four unique digits.\u003c/p\u003e","function_template":"function temp=diff_digits(start,finish)\r\n\r\ntemp=start-finish\r\n\r\nend","test_suite":"%%\r\nstart=1000; finish=1023; y_correct = 1;\r\nassert(isequal(diff_digits(start,finish),y_correct))\r\n%%\r\nstart=1000; finish=9999; y_correct = 4536;\r\nassert(isequal(diff_digits(start,finish),y_correct))\r\n%%\r\nstart=1234; finish=5678; y_correct = 2273;\r\nassert(isequal(diff_digits(start,finish),y_correct))\r\n%%\r\nassert(isequal(diff_digits(4321,6789),1210))\r\n%%\r\nassert(isequal(diff_digits(1988,2012),0))","published":true,"deleted":false,"likes_count":10,"comments_count":3,"created_by":1615,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":193,"test_suite_updated_at":"2018-05-24T11:43:36.000Z","rescore_all_solutions":true,"group_id":44,"created_at":"2013-01-02T16:17:59.000Z","updated_at":"2026-02-07T16:08:31.000Z","published_at":"2013-01-02T16:20:24.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eHappy 2013, everyone! An interesting tidbit about 2013 is that it is the first year since 1987 to contain four different digits. Write a MATLAB function that, when given a start year and an end year, will tell you how many of the years between these two values have four unique digits. You may assume that the years will only have four digits, and that the start year will be smaller than the end year.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003cw:jc w:val=\\\"left\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor example: if start=1000 and finish=1023, your output should be 1, as 1023 is the only year in that range that has four unique digits.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray 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