{"group":{"id":1,"name":"Community","lockable":false,"created_at":"2012-01-18T18:02:15.000Z","updated_at":"2025-12-14T01:33:56.000Z","description":"Problems submitted by members of the MATLAB Central community.","is_default":true,"created_by":161519,"badge_id":null,"featured":false,"trending":false,"solution_count_in_trending_period":0,"trending_last_calculated":"2025-12-14T00:00:00.000Z","image_id":null,"published":true,"community_created":false,"status_id":2,"is_default_group_for_player":false,"deleted_by":null,"deleted_at":null,"restored_by":null,"restored_at":null,"description_opc":null,"description_html":null,"published_at":null},"problems":[{"id":2389,"title":"Max of a Vector","description":"Write a function to return the max of a vector","description_html":"\u003cp\u003eWrite a function to return the max of a vector\u003c/p\u003e","function_template":"function y = FindMax(x)\r\n  \r\nend","test_suite":"%%\r\nx = [10 20 30];\r\ny_correct = 30;\r\nassert(isequal(FindMax(x),  y_correct))\r\n\r\n%%\r\nx = [1 2 3 4 3 2 1];\r\ny_correct = 4;\r\nassert(isequal(FindMax(x),   y_correct))\r\n","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":721,"test_suite_updated_at":"2014-06-25T20:05:00.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2014-06-25T20:02:30.000Z","updated_at":"2026-03-29T23:34:58.000Z","published_at":"2014-06-25T20:02:30.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eWrite a function to return the max of a vector\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2509,"title":"Wind Chill Computation","description":"On a windy day, a temperature of 15 degrees may feel colder, perhaps 7 degrees. The formula below calculates the \"wind chill,\" indicating the temperature that is felt based on the actual temperature (T, in Fahrenheit) and wind speed (W, in miles per hour):\r\n\r\n  windChill = 35.7 + 0.6T - 35.7W^0.16 + 0.43TW^0.16\r\n\r\nComplete the function to compute wind chill. Note: While math notation uses abutment for multiplication, as in 5y, MATLAB requires use of * when multiplying items, as in 5*y.","description_html":"\u003cp\u003eOn a windy day, a temperature of 15 degrees may feel colder, perhaps 7 degrees. The formula below calculates the \"wind chill,\" indicating the temperature that is felt based on the actual temperature (T, in Fahrenheit) and wind speed (W, in miles per hour):\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003ewindChill = 35.7 + 0.6T - 35.7W^0.16 + 0.43TW^0.16\r\n\u003c/pre\u003e\u003cp\u003eComplete the function to compute wind chill. Note: While math notation uses abutment for multiplication, as in 5y, MATLAB requires use of * when multiplying items, as in 5*y.\u003c/p\u003e","function_template":"function windChill = ComputeWindChill(T, W)\r\n  windChill = ... ;\r\nend","test_suite":"%%\r\nwc_correct1 = 23.1871;\r\nwc_result1  = ComputeWindChill(32, 10);\r\nassert(abs(wc_result1 - wc_correct1) \u003c 0.0001)\r\n%%\r\nwc_correct2 = -9.0101;\r\nwc_result2  = ComputeWindChill(10, 20);\r\nassert(abs(wc_result2 - wc_correct2) \u003c 0.0001)\r\n%%\r\nwc_correct3 = 17.4215;\r\nwc_result3  = ComputeWindChill(20, 2);\r\nassert(abs(wc_result3 - wc_correct3) \u003c 0.0001)\r\n","published":true,"deleted":false,"likes_count":5,"comments_count":0,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":560,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2014-08-14T22:08:29.000Z","updated_at":"2026-02-17T08:49:29.000Z","published_at":"2014-08-14T22:37:06.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eOn a windy day, a temperature of 15 degrees may feel colder, perhaps 7 degrees. The formula below calculates the \\\"wind chill,\\\" indicating the temperature that is felt based on the actual temperature (T, in Fahrenheit) and wind speed (W, in miles per hour):\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[windChill = 35.7 + 0.6T - 35.7W^0.16 + 0.43TW^0.16]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eComplete the function to compute wind chill. Note: While math notation uses abutment for multiplication, as in 5y, MATLAB requires use of * when multiplying items, as in 5*y.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2510,"title":"Solving Quadratic Equations (Version 1)","description":"Quadratic equations have the form: ax^2 + bx + c = 0. Example: x^2 + 3x + 2 = 0, where a = 1, b = 3, and c = 2. The equation has 2 real solutions (roots): x = -1 and x = -2.  The quadratic formula can be used to find the roots:\r\n\r\n\u003c\u003chttps://dl.dropboxusercontent.com/u/57773343/__IMAGES/QuadraticSolution1.gif\u003e\u003e\r\n\r\nThe formula can be translated into the computation of two roots x1 and x2:\r\n\r\n  x1 = -b + ...\r\n  x2 = -b - ...\r\n\r\nComplete the function to solve the quadratic equation denoted by a, b, and c.  Assume the _discriminant_ --- b^2 - 4ac --- is not negative, ensuring that x1 and x2 are real. ","description_html":"\u003cp\u003eQuadratic equations have the form: ax^2 + bx + c = 0. Example: x^2 + 3x + 2 = 0, where a = 1, b = 3, and c = 2. The equation has 2 real solutions (roots): x = -1 and x = -2.  The quadratic formula can be used to find the roots:\u003c/p\u003e\u003cimg src = \"https://dl.dropboxusercontent.com/u/57773343/__IMAGES/QuadraticSolution1.gif\"\u003e\u003cp\u003eThe formula can be translated into the computation of two roots x1 and x2:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003ex1 = -b + ...\r\nx2 = -b - ...\r\n\u003c/pre\u003e\u003cp\u003eComplete the function to solve the quadratic equation denoted by a, b, and c.  Assume the \u003ci\u003ediscriminant\u003c/i\u003e --- b^2 - 4ac --- is not negative, ensuring that x1 and x2 are real.\u003c/p\u003e","function_template":"function [x1, x2] = SolveQuadraticEquation(a, b, c)\r\n  x1 = -b + ... ;\r\n  x2 = -b - ... ;\r\nend\r\n","test_suite":"%%\r\nqe_correct1_1 = -1;\r\nqe_correct1_2 = -2;\r\n[qe_result1_1, qe_result1_2] = SolveQuadraticEquation(1, 3, 2);\r\nassert( (abs(qe_result1_1 - qe_correct1_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result1_2 - qe_correct1_2) \u003c 0.0001) || ...\r\n        (abs(qe_result1_1 - qe_correct1_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result1_2 - qe_correct1_1) \u003c 0.0001) );\r\n%%\r\nqe_correct2_1 = 0.224745;\r\nqe_correct2_2 = -2.22474;\r\n[qe_result2_1, qe_result2_2] = SolveQuadraticEquation(2, 4, -1);\r\nassert( (abs(qe_result2_1 - qe_correct2_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result2_2 - qe_correct2_2) \u003c 0.0001) || ...\r\n        (abs(qe_result2_1 - qe_correct2_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result2_2 - qe_correct2_1) \u003c 0.0001) );\r\n%%\r\nqe_correct3_1 = -1;\r\nqe_correct3_2 = -1;\r\n[qe_result3_1, qe_result3_2] = SolveQuadraticEquation(2, 4, 2);\r\nassert( (abs(qe_result3_1 - qe_correct3_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result3_2 - qe_correct3_2) \u003c 0.0001) || ...\r\n        (abs(qe_result3_1 - qe_correct3_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result3_2 - qe_correct3_1) \u003c 0.0001) );\r\n","published":true,"deleted":false,"likes_count":3,"comments_count":0,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":505,"test_suite_updated_at":"2014-08-15T09:50:02.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2014-08-14T23:08:09.000Z","updated_at":"2026-03-31T12:44:20.000Z","published_at":"2014-08-15T09:50:02.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/media/image1.gif\"}],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eQuadratic equations have the form: ax^2 + bx + c = 0. Example: x^2 + 3x + 2 = 0, where a = 1, b = 3, and c = 2. The equation has 2 real solutions (roots): x = -1 and x = -2. The quadratic formula can be used to find the roots:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe formula can be translated into the computation of two roots x1 and x2:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[x1 = -b + ...\\nx2 = -b - ...]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eComplete the function to solve the quadratic equation denoted by a, b, and c. Assume the\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ediscriminant\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e --- b^2 - 4ac --- is not negative, ensuring that x1 and x2 are real.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"},{\"partUri\":\"/media/image1.gif\",\"contentType\":\"image/gif\",\"content\":\"data:image/gif;base64,iVBORw0KGgoAAAANSUhEUgAAACAAAAAgCAMAAABEpIrGAAAAGXRFWHRTb2Z0d2FyZQBBZG9iZSBJbWFnZVJlYWR5ccllPAAAAC1QTFRFeHh4k5OT9vb2gYGBnJycwMDAt7e3ioqK0tLS7e3t29vb5OTkycnJ////b29vvCMpXwAAAKZJREFUeNq8k0sWwyAIAEXzh3D/41ZrahASklXZ6cxTEAz8EOGFsDvxTyECM0RHgJIwOEIt6VFYX19BAd0kKe8vTpn0vY9uheXoQjGYrICtf9mg3Qgo+kt12fE4sxQwaGFQXCdJmmshaV4EnKYxmgMO/pvJVJ92NrwNbSpnrJafUz1kYbRcjP121ii4EKDVIPnVx+n4hdBzKyhuBM21YLgSLOePAAMAW0UziCh1I3kAAAAASUVORK5CYII=\"}]}"},{"id":2609,"title":"If-then-else","description":"Complete the function below such that if the value of x is in the range 10 to 14, inclusive, the value 18 is assigned to y.  Otherwise 7 is assigned to y.\r\n  ","description_html":"\u003cp\u003eComplete the function below such that if the value of x is in the range 10 to 14, inclusive, the value 18 is assigned to y.  Otherwise 7 is assigned to y.\u003c/p\u003e","function_template":"function y = if_then_else(x)\r\n  ???\r\nend","test_suite":"%%\r\nx = 10;\r\ny_correct = 18;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 14;\r\ny_correct = 18;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 11;\r\ny_correct = 18;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 12;\r\ny_correct = 18;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 13;\r\ny_correct = 18;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 9;\r\ny_correct = 7;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 15;\r\ny_correct = 7;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 0;\r\ny_correct = 7;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 100;\r\ny_correct = 7;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = -2;\r\ny_correct = 7;\r\nassert(isequal(if_then_else(x),y_correct))\r\n","published":true,"deleted":false,"likes_count":5,"comments_count":0,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":391,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2014-09-29T06:00:18.000Z","updated_at":"2026-02-18T14:51:46.000Z","published_at":"2014-09-29T06:00:27.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eComplete the function below such that if the value of x is in the range 10 to 14, inclusive, the value 18 is assigned to y. Otherwise 7 is assigned to y.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2529,"title":"Solving Quadratic Equations (Version 2)","description":"Before attempting this problem, solve version 1:  \u003chttps://www.mathworks.com/matlabcentral/cody/problems/2510-solving-quadratic-equations-version-1\u003e.\r\n\r\nIn this version, the discriminant can have any value.  Complete the function so if the discriminant is negative, the function returns values of NaN --- \"Not a Number\" --- for x1 and x2.  Otherwise, the function computes x1 and x2 as before using the formula\r\n\r\n\u003c\u003chttps://dl.dropboxusercontent.com/u/57773343/__IMAGES/QuadraticSolution1.gif\u003e\u003e\r\n","description_html":"\u003cp\u003eBefore attempting this problem, solve version 1:  \u003ca href = \"https://www.mathworks.com/matlabcentral/cody/problems/2510-solving-quadratic-equations-version-1\"\u003ehttps://www.mathworks.com/matlabcentral/cody/problems/2510-solving-quadratic-equations-version-1\u003c/a\u003e.\u003c/p\u003e\u003cp\u003eIn this version, the discriminant can have any value.  Complete the function so if the discriminant is negative, the function returns values of NaN --- \"Not a Number\" --- for x1 and x2.  Otherwise, the function computes x1 and x2 as before using the formula\u003c/p\u003e\u003cimg src = \"https://dl.dropboxusercontent.com/u/57773343/__IMAGES/QuadraticSolution1.gif\"\u003e","function_template":"function [x1, x2] = SolveQuadraticEquation(a, b, c)\r\n\r\nend","test_suite":"%%\r\nqe_correct1_1 = -1;\r\nqe_correct1_2 = -2;\r\n[qe_result1_1, qe_result1_2] = SolveQuadraticEquation(1, 3, 2);\r\nassert( (abs(qe_result1_1 - qe_correct1_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result1_2 - qe_correct1_2) \u003c 0.0001) || ...\r\n        (abs(qe_result1_1 - qe_correct1_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result1_2 - qe_correct1_1) \u003c 0.0001) );\r\n%%\r\nqe_correct2_1 = 0.224745;\r\nqe_correct2_2 = -2.22474;\r\n[qe_result2_1, qe_result2_2] = SolveQuadraticEquation(2, 4, -1);\r\nassert( (abs(qe_result2_1 - qe_correct2_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result2_2 - qe_correct2_2) \u003c 0.0001) || ...\r\n        (abs(qe_result2_1 - qe_correct2_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result2_2 - qe_correct2_1) \u003c 0.0001) );\r\n%%\r\nqe_correct3_1 = -1;\r\nqe_correct3_2 = -1;\r\n[qe_result3_1, qe_result3_2] = SolveQuadraticEquation(2, 4, 2);\r\nassert( (abs(qe_result3_1 - qe_correct3_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result3_2 - qe_correct3_2) \u003c 0.0001) || ...\r\n        (abs(qe_result3_1 - qe_correct3_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result3_2 - qe_correct3_1) \u003c 0.0001) );\r\n%%\r\n[qe_result4_1, qe_result4_2] = SolveQuadraticEquation(4, 4, 4);\r\nassert( isnan(qe_result4_1) \u0026\u0026 isnan(qe_result4_2) );\r\n%%\r\n[qe_result5_1, qe_result5_2] = SolveQuadraticEquation(9.1, 12, 4.1);\r\nassert( isnan(qe_result5_1) \u0026\u0026 isnan(qe_result5_2) );\r\n","published":true,"deleted":false,"likes_count":0,"comments_count":1,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":90,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2014-08-25T23:26:04.000Z","updated_at":"2026-03-16T12:13:52.000Z","published_at":"2014-08-25T23:42:27.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/media/image1.gif\"}],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eBefore attempting this problem, solve version 1: \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"https://www.mathworks.com/matlabcentral/cody/problems/2510-solving-quadratic-equations-version-1\\\"\u003e\u003cw:r\u003e\u003cw:t\u003e\u0026lt;https://www.mathworks.com/matlabcentral/cody/problems/2510-solving-quadratic-equations-version-1\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e\u0026gt;.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eIn this version, the discriminant can have any value. Complete the function so if the discriminant is negative, the function returns values of NaN --- \\\"Not a Number\\\" --- for x1 and x2. Otherwise, the function computes x1 and x2 as before using the formula\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"},{\"partUri\":\"/media/image1.gif\",\"contentType\":\"image/gif\",\"content\":\"data:image/gif;base64,iVBORw0KGgoAAAANSUhEUgAAACAAAAAgCAMAAABEpIrGAAAAGXRFWHRTb2Z0d2FyZQBBZG9iZSBJbWFnZVJlYWR5ccllPAAAAC1QTFRFeHh4k5OT9vb2gYGBnJycwMDAt7e3ioqK0tLS7e3t29vb5OTkycnJ////b29vvCMpXwAAAKZJREFUeNq8k0sWwyAIAEXzh3D/41ZrahASklXZ6cxTEAz8EOGFsDvxTyECM0RHgJIwOEIt6VFYX19BAd0kKe8vTpn0vY9uheXoQjGYrICtf9mg3Qgo+kt12fE4sxQwaGFQXCdJmmshaV4EnKYxmgMO/pvJVJ92NrwNbSpnrJafUz1kYbRcjP121ii4EKDVIPnVx+n4hdBzKyhuBM21YLgSLOePAAMAW0UziCh1I3kAAAAASUVORK5CYII=\"}]}"},{"id":2530,"title":"Powers Of","description":"Fill the vector with powers of 2, so that vector(1) is 2^1, vector(2) is 2^2, etc. Stop with vector(10).  Complete the function using a *for* loop.","description_html":"\u003cp\u003eFill the vector with powers of 2, so that vector(1) is 2^1, vector(2) is 2^2, etc. Stop with vector(10).  Complete the function using a \u003cb\u003efor\u003c/b\u003e loop.\u003c/p\u003e","function_template":"function vector = PowersOf(vector)\r\n  for ?\r\n    ?\r\n  end\r\nend","test_suite":"%%\r\nvector1 = [0 0 0 0 0 0 0 0 0 0];\r\nvector1_correct = [2 4 8 16 32 64 128 256 512 1024];\r\ncode = textread('PowersOf.m', '%s');\r\nassert(isequal(PowersOf(vector1), vector1_correct) \u0026\u0026 ...\r\n       strcmp(code(5), 'for') \u0026\u0026 ...\r\n       strcmp(code(end-7), 'end') \u0026\u0026 ...\r\n       strcmp(code(end-6), 'end'));","published":true,"deleted":false,"likes_count":2,"comments_count":1,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":108,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2014-08-26T12:47:32.000Z","updated_at":"2026-03-22T17:55:53.000Z","published_at":"2014-08-26T13:56:12.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFill the vector with powers of 2, so that vector(1) is 2^1, vector(2) is 2^2, etc. Stop with vector(10). Complete the function using a\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003efor\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e loop.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2610,"title":"counting for loop","description":"Complete the function below using a for loop to count from 3 to N by 2.  For example, if N is 10, count 3, 5, 7, 9 and stop.  For each value v, call the function mydisplay(v).  Note that N could be less than 3, in which case mydisplay() should never be called.","description_html":"\u003cp\u003eComplete the function below using a for loop to count from 3 to N by 2.  For example, if N is 10, count 3, 5, 7, 9 and stop.  For each value v, call the function mydisplay(v).  Note that N could be less than 3, in which case mydisplay() should never be called.\u003c/p\u003e","function_template":"function [] = counting_loop(N)\r\n  for ???\r\nend\r\n\r\nfunction mydisplay(v)\r\n  global gRV ;\r\n  gRV(end+1) = v ;\r\nend ","test_suite":"%%\r\nglobal gRV;\r\ngRV = [];\r\nN   = 10;\r\ngRV_correct = [3 5 7 9];\r\ncounting_loop(N);\r\ncode = textread('counting_loop.m', '%s');\r\nassert(isequal(gRV, gRV_correct) \u0026\u0026 strcmp(code(5), 'for'));\r\n%%\r\nglobal gRV;\r\ngRV = [];\r\nN   = 5;\r\ngRV_correct = [3 5];\r\ncounting_loop(N);\r\ncode = textread('counting_loop.m', '%s');\r\nassert(isequal(gRV, gRV_correct) \u0026\u0026 strcmp(code(5), 'for'));\r\n%%\r\nglobal gRV;\r\ngRV = [];\r\nN   = 3;\r\ngRV_correct = [3];\r\ncounting_loop(N);\r\ncode = textread('counting_loop.m', '%s');\r\nassert(isequal(gRV, gRV_correct) \u0026\u0026 strcmp(code(5), 'for'));\r\n%%\r\nglobal gRV;\r\ngRV = [];\r\nN   = 0;\r\ngRV_correct = [];\r\ncounting_loop(N);\r\ncode = textread('counting_loop.m', '%s');\r\nassert(isequal(gRV, gRV_correct) \u0026\u0026 strcmp(code(5), 'for'));\r\n%%\r\nglobal gRV;\r\ngRV = [];\r\nN   = 39;\r\ngRV_correct = [3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39];\r\ncounting_loop(N);\r\ncode = textread('counting_loop.m', '%s');\r\nassert(isequal(gRV, gRV_correct) \u0026\u0026 strcmp(code(5), 'for'));","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":60,"test_suite_updated_at":"2014-09-30T07:12:50.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2014-09-29T06:04:35.000Z","updated_at":"2026-03-06T11:34:21.000Z","published_at":"2014-09-30T07:12:50.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eComplete the function below using a for loop to count from 3 to N by 2. For example, if N is 10, count 3, 5, 7, 9 and stop. For each value v, call the function mydisplay(v). Note that N could be less than 3, in which case mydisplay() should never be called.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"errors":[],"problems":[{"id":2389,"title":"Max of a Vector","description":"Write a function to return the max of a vector","description_html":"\u003cp\u003eWrite a function to return the max of a vector\u003c/p\u003e","function_template":"function y = FindMax(x)\r\n  \r\nend","test_suite":"%%\r\nx = [10 20 30];\r\ny_correct = 30;\r\nassert(isequal(FindMax(x),  y_correct))\r\n\r\n%%\r\nx = [1 2 3 4 3 2 1];\r\ny_correct = 4;\r\nassert(isequal(FindMax(x),   y_correct))\r\n","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":721,"test_suite_updated_at":"2014-06-25T20:05:00.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2014-06-25T20:02:30.000Z","updated_at":"2026-03-29T23:34:58.000Z","published_at":"2014-06-25T20:02:30.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eWrite a function to return the max of a vector\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2509,"title":"Wind Chill Computation","description":"On a windy day, a temperature of 15 degrees may feel colder, perhaps 7 degrees. The formula below calculates the \"wind chill,\" indicating the temperature that is felt based on the actual temperature (T, in Fahrenheit) and wind speed (W, in miles per hour):\r\n\r\n  windChill = 35.7 + 0.6T - 35.7W^0.16 + 0.43TW^0.16\r\n\r\nComplete the function to compute wind chill. Note: While math notation uses abutment for multiplication, as in 5y, MATLAB requires use of * when multiplying items, as in 5*y.","description_html":"\u003cp\u003eOn a windy day, a temperature of 15 degrees may feel colder, perhaps 7 degrees. The formula below calculates the \"wind chill,\" indicating the temperature that is felt based on the actual temperature (T, in Fahrenheit) and wind speed (W, in miles per hour):\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003ewindChill = 35.7 + 0.6T - 35.7W^0.16 + 0.43TW^0.16\r\n\u003c/pre\u003e\u003cp\u003eComplete the function to compute wind chill. Note: While math notation uses abutment for multiplication, as in 5y, MATLAB requires use of * when multiplying items, as in 5*y.\u003c/p\u003e","function_template":"function windChill = ComputeWindChill(T, W)\r\n  windChill = ... ;\r\nend","test_suite":"%%\r\nwc_correct1 = 23.1871;\r\nwc_result1  = ComputeWindChill(32, 10);\r\nassert(abs(wc_result1 - wc_correct1) \u003c 0.0001)\r\n%%\r\nwc_correct2 = -9.0101;\r\nwc_result2  = ComputeWindChill(10, 20);\r\nassert(abs(wc_result2 - wc_correct2) \u003c 0.0001)\r\n%%\r\nwc_correct3 = 17.4215;\r\nwc_result3  = ComputeWindChill(20, 2);\r\nassert(abs(wc_result3 - wc_correct3) \u003c 0.0001)\r\n","published":true,"deleted":false,"likes_count":5,"comments_count":0,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":560,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2014-08-14T22:08:29.000Z","updated_at":"2026-02-17T08:49:29.000Z","published_at":"2014-08-14T22:37:06.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eOn a windy day, a temperature of 15 degrees may feel colder, perhaps 7 degrees. The formula below calculates the \\\"wind chill,\\\" indicating the temperature that is felt based on the actual temperature (T, in Fahrenheit) and wind speed (W, in miles per hour):\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[windChill = 35.7 + 0.6T - 35.7W^0.16 + 0.43TW^0.16]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eComplete the function to compute wind chill. Note: While math notation uses abutment for multiplication, as in 5y, MATLAB requires use of * when multiplying items, as in 5*y.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2510,"title":"Solving Quadratic Equations (Version 1)","description":"Quadratic equations have the form: ax^2 + bx + c = 0. Example: x^2 + 3x + 2 = 0, where a = 1, b = 3, and c = 2. The equation has 2 real solutions (roots): x = -1 and x = -2.  The quadratic formula can be used to find the roots:\r\n\r\n\u003c\u003chttps://dl.dropboxusercontent.com/u/57773343/__IMAGES/QuadraticSolution1.gif\u003e\u003e\r\n\r\nThe formula can be translated into the computation of two roots x1 and x2:\r\n\r\n  x1 = -b + ...\r\n  x2 = -b - ...\r\n\r\nComplete the function to solve the quadratic equation denoted by a, b, and c.  Assume the _discriminant_ --- b^2 - 4ac --- is not negative, ensuring that x1 and x2 are real. ","description_html":"\u003cp\u003eQuadratic equations have the form: ax^2 + bx + c = 0. Example: x^2 + 3x + 2 = 0, where a = 1, b = 3, and c = 2. The equation has 2 real solutions (roots): x = -1 and x = -2.  The quadratic formula can be used to find the roots:\u003c/p\u003e\u003cimg src = \"https://dl.dropboxusercontent.com/u/57773343/__IMAGES/QuadraticSolution1.gif\"\u003e\u003cp\u003eThe formula can be translated into the computation of two roots x1 and x2:\u003c/p\u003e\u003cpre class=\"language-matlab\"\u003ex1 = -b + ...\r\nx2 = -b - ...\r\n\u003c/pre\u003e\u003cp\u003eComplete the function to solve the quadratic equation denoted by a, b, and c.  Assume the \u003ci\u003ediscriminant\u003c/i\u003e --- b^2 - 4ac --- is not negative, ensuring that x1 and x2 are real.\u003c/p\u003e","function_template":"function [x1, x2] = SolveQuadraticEquation(a, b, c)\r\n  x1 = -b + ... ;\r\n  x2 = -b - ... ;\r\nend\r\n","test_suite":"%%\r\nqe_correct1_1 = -1;\r\nqe_correct1_2 = -2;\r\n[qe_result1_1, qe_result1_2] = SolveQuadraticEquation(1, 3, 2);\r\nassert( (abs(qe_result1_1 - qe_correct1_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result1_2 - qe_correct1_2) \u003c 0.0001) || ...\r\n        (abs(qe_result1_1 - qe_correct1_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result1_2 - qe_correct1_1) \u003c 0.0001) );\r\n%%\r\nqe_correct2_1 = 0.224745;\r\nqe_correct2_2 = -2.22474;\r\n[qe_result2_1, qe_result2_2] = SolveQuadraticEquation(2, 4, -1);\r\nassert( (abs(qe_result2_1 - qe_correct2_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result2_2 - qe_correct2_2) \u003c 0.0001) || ...\r\n        (abs(qe_result2_1 - qe_correct2_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result2_2 - qe_correct2_1) \u003c 0.0001) );\r\n%%\r\nqe_correct3_1 = -1;\r\nqe_correct3_2 = -1;\r\n[qe_result3_1, qe_result3_2] = SolveQuadraticEquation(2, 4, 2);\r\nassert( (abs(qe_result3_1 - qe_correct3_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result3_2 - qe_correct3_2) \u003c 0.0001) || ...\r\n        (abs(qe_result3_1 - qe_correct3_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result3_2 - qe_correct3_1) \u003c 0.0001) );\r\n","published":true,"deleted":false,"likes_count":3,"comments_count":0,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":505,"test_suite_updated_at":"2014-08-15T09:50:02.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2014-08-14T23:08:09.000Z","updated_at":"2026-03-31T12:44:20.000Z","published_at":"2014-08-15T09:50:02.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/media/image1.gif\"}],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eQuadratic equations have the form: ax^2 + bx + c = 0. Example: x^2 + 3x + 2 = 0, where a = 1, b = 3, and c = 2. The equation has 2 real solutions (roots): x = -1 and x = -2. The quadratic formula can be used to find the roots:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe formula can be translated into the computation of two roots x1 and x2:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[x1 = -b + ...\\nx2 = -b - ...]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eComplete the function to solve the quadratic equation denoted by a, b, and c. Assume the\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ediscriminant\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e --- b^2 - 4ac --- is not negative, ensuring that x1 and x2 are real.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"},{\"partUri\":\"/media/image1.gif\",\"contentType\":\"image/gif\",\"content\":\"data:image/gif;base64,iVBORw0KGgoAAAANSUhEUgAAACAAAAAgCAMAAABEpIrGAAAAGXRFWHRTb2Z0d2FyZQBBZG9iZSBJbWFnZVJlYWR5ccllPAAAAC1QTFRFeHh4k5OT9vb2gYGBnJycwMDAt7e3ioqK0tLS7e3t29vb5OTkycnJ////b29vvCMpXwAAAKZJREFUeNq8k0sWwyAIAEXzh3D/41ZrahASklXZ6cxTEAz8EOGFsDvxTyECM0RHgJIwOEIt6VFYX19BAd0kKe8vTpn0vY9uheXoQjGYrICtf9mg3Qgo+kt12fE4sxQwaGFQXCdJmmshaV4EnKYxmgMO/pvJVJ92NrwNbSpnrJafUz1kYbRcjP121ii4EKDVIPnVx+n4hdBzKyhuBM21YLgSLOePAAMAW0UziCh1I3kAAAAASUVORK5CYII=\"}]}"},{"id":2609,"title":"If-then-else","description":"Complete the function below such that if the value of x is in the range 10 to 14, inclusive, the value 18 is assigned to y.  Otherwise 7 is assigned to y.\r\n  ","description_html":"\u003cp\u003eComplete the function below such that if the value of x is in the range 10 to 14, inclusive, the value 18 is assigned to y.  Otherwise 7 is assigned to y.\u003c/p\u003e","function_template":"function y = if_then_else(x)\r\n  ???\r\nend","test_suite":"%%\r\nx = 10;\r\ny_correct = 18;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 14;\r\ny_correct = 18;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 11;\r\ny_correct = 18;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 12;\r\ny_correct = 18;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 13;\r\ny_correct = 18;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 9;\r\ny_correct = 7;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 15;\r\ny_correct = 7;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 0;\r\ny_correct = 7;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = 100;\r\ny_correct = 7;\r\nassert(isequal(if_then_else(x),y_correct))\r\n%%\r\nx = -2;\r\ny_correct = 7;\r\nassert(isequal(if_then_else(x),y_correct))\r\n","published":true,"deleted":false,"likes_count":5,"comments_count":0,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":391,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2014-09-29T06:00:18.000Z","updated_at":"2026-02-18T14:51:46.000Z","published_at":"2014-09-29T06:00:27.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eComplete the function below such that if the value of x is in the range 10 to 14, inclusive, the value 18 is assigned to y. Otherwise 7 is assigned to y.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2529,"title":"Solving Quadratic Equations (Version 2)","description":"Before attempting this problem, solve version 1:  \u003chttps://www.mathworks.com/matlabcentral/cody/problems/2510-solving-quadratic-equations-version-1\u003e.\r\n\r\nIn this version, the discriminant can have any value.  Complete the function so if the discriminant is negative, the function returns values of NaN --- \"Not a Number\" --- for x1 and x2.  Otherwise, the function computes x1 and x2 as before using the formula\r\n\r\n\u003c\u003chttps://dl.dropboxusercontent.com/u/57773343/__IMAGES/QuadraticSolution1.gif\u003e\u003e\r\n","description_html":"\u003cp\u003eBefore attempting this problem, solve version 1:  \u003ca href = \"https://www.mathworks.com/matlabcentral/cody/problems/2510-solving-quadratic-equations-version-1\"\u003ehttps://www.mathworks.com/matlabcentral/cody/problems/2510-solving-quadratic-equations-version-1\u003c/a\u003e.\u003c/p\u003e\u003cp\u003eIn this version, the discriminant can have any value.  Complete the function so if the discriminant is negative, the function returns values of NaN --- \"Not a Number\" --- for x1 and x2.  Otherwise, the function computes x1 and x2 as before using the formula\u003c/p\u003e\u003cimg src = \"https://dl.dropboxusercontent.com/u/57773343/__IMAGES/QuadraticSolution1.gif\"\u003e","function_template":"function [x1, x2] = SolveQuadraticEquation(a, b, c)\r\n\r\nend","test_suite":"%%\r\nqe_correct1_1 = -1;\r\nqe_correct1_2 = -2;\r\n[qe_result1_1, qe_result1_2] = SolveQuadraticEquation(1, 3, 2);\r\nassert( (abs(qe_result1_1 - qe_correct1_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result1_2 - qe_correct1_2) \u003c 0.0001) || ...\r\n        (abs(qe_result1_1 - qe_correct1_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result1_2 - qe_correct1_1) \u003c 0.0001) );\r\n%%\r\nqe_correct2_1 = 0.224745;\r\nqe_correct2_2 = -2.22474;\r\n[qe_result2_1, qe_result2_2] = SolveQuadraticEquation(2, 4, -1);\r\nassert( (abs(qe_result2_1 - qe_correct2_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result2_2 - qe_correct2_2) \u003c 0.0001) || ...\r\n        (abs(qe_result2_1 - qe_correct2_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result2_2 - qe_correct2_1) \u003c 0.0001) );\r\n%%\r\nqe_correct3_1 = -1;\r\nqe_correct3_2 = -1;\r\n[qe_result3_1, qe_result3_2] = SolveQuadraticEquation(2, 4, 2);\r\nassert( (abs(qe_result3_1 - qe_correct3_1) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result3_2 - qe_correct3_2) \u003c 0.0001) || ...\r\n        (abs(qe_result3_1 - qe_correct3_2) \u003c 0.0001  \u0026\u0026 ...\r\n         abs(qe_result3_2 - qe_correct3_1) \u003c 0.0001) );\r\n%%\r\n[qe_result4_1, qe_result4_2] = SolveQuadraticEquation(4, 4, 4);\r\nassert( isnan(qe_result4_1) \u0026\u0026 isnan(qe_result4_2) );\r\n%%\r\n[qe_result5_1, qe_result5_2] = SolveQuadraticEquation(9.1, 12, 4.1);\r\nassert( isnan(qe_result5_1) \u0026\u0026 isnan(qe_result5_2) );\r\n","published":true,"deleted":false,"likes_count":0,"comments_count":1,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":90,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2014-08-25T23:26:04.000Z","updated_at":"2026-03-16T12:13:52.000Z","published_at":"2014-08-25T23:42:27.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/image\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/media/image1.gif\"}],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eBefore attempting this problem, solve version 1: \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:hyperlink w:docLocation=\\\"https://www.mathworks.com/matlabcentral/cody/problems/2510-solving-quadratic-equations-version-1\\\"\u003e\u003cw:r\u003e\u003cw:t\u003e\u0026lt;https://www.mathworks.com/matlabcentral/cody/problems/2510-solving-quadratic-equations-version-1\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003cw:r\u003e\u003cw:t\u003e\u0026gt;.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eIn this version, the discriminant can have any value. Complete the function so if the discriminant is negative, the function returns values of NaN --- \\\"Not a Number\\\" --- for x1 and x2. Otherwise, the function computes x1 and x2 as before using the formula\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:customXml w:element=\\\"image\\\"\u003e\u003cw:customXmlPr\u003e\u003cw:attr w:name=\\\"height\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"width\\\" w:val=\\\"-1\\\"/\u003e\u003cw:attr w:name=\\\"relationshipId\\\" w:val=\\\"rId1\\\"/\u003e\u003c/w:customXmlPr\u003e\u003c/w:customXml\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"},{\"partUri\":\"/media/image1.gif\",\"contentType\":\"image/gif\",\"content\":\"data:image/gif;base64,iVBORw0KGgoAAAANSUhEUgAAACAAAAAgCAMAAABEpIrGAAAAGXRFWHRTb2Z0d2FyZQBBZG9iZSBJbWFnZVJlYWR5ccllPAAAAC1QTFRFeHh4k5OT9vb2gYGBnJycwMDAt7e3ioqK0tLS7e3t29vb5OTkycnJ////b29vvCMpXwAAAKZJREFUeNq8k0sWwyAIAEXzh3D/41ZrahASklXZ6cxTEAz8EOGFsDvxTyECM0RHgJIwOEIt6VFYX19BAd0kKe8vTpn0vY9uheXoQjGYrICtf9mg3Qgo+kt12fE4sxQwaGFQXCdJmmshaV4EnKYxmgMO/pvJVJ92NrwNbSpnrJafUz1kYbRcjP121ii4EKDVIPnVx+n4hdBzKyhuBM21YLgSLOePAAMAW0UziCh1I3kAAAAASUVORK5CYII=\"}]}"},{"id":2530,"title":"Powers Of","description":"Fill the vector with powers of 2, so that vector(1) is 2^1, vector(2) is 2^2, etc. Stop with vector(10).  Complete the function using a *for* loop.","description_html":"\u003cp\u003eFill the vector with powers of 2, so that vector(1) is 2^1, vector(2) is 2^2, etc. Stop with vector(10).  Complete the function using a \u003cb\u003efor\u003c/b\u003e loop.\u003c/p\u003e","function_template":"function vector = PowersOf(vector)\r\n  for ?\r\n    ?\r\n  end\r\nend","test_suite":"%%\r\nvector1 = [0 0 0 0 0 0 0 0 0 0];\r\nvector1_correct = [2 4 8 16 32 64 128 256 512 1024];\r\ncode = textread('PowersOf.m', '%s');\r\nassert(isequal(PowersOf(vector1), vector1_correct) \u0026\u0026 ...\r\n       strcmp(code(5), 'for') \u0026\u0026 ...\r\n       strcmp(code(end-7), 'end') \u0026\u0026 ...\r\n       strcmp(code(end-6), 'end'));","published":true,"deleted":false,"likes_count":2,"comments_count":1,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":108,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":1,"created_at":"2014-08-26T12:47:32.000Z","updated_at":"2026-03-22T17:55:53.000Z","published_at":"2014-08-26T13:56:12.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFill the vector with powers of 2, so that vector(1) is 2^1, vector(2) is 2^2, etc. Stop with vector(10). Complete the function using a\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003efor\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e loop.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"},{"id":2610,"title":"counting for loop","description":"Complete the function below using a for loop to count from 3 to N by 2.  For example, if N is 10, count 3, 5, 7, 9 and stop.  For each value v, call the function mydisplay(v).  Note that N could be less than 3, in which case mydisplay() should never be called.","description_html":"\u003cp\u003eComplete the function below using a for loop to count from 3 to N by 2.  For example, if N is 10, count 3, 5, 7, 9 and stop.  For each value v, call the function mydisplay(v).  Note that N could be less than 3, in which case mydisplay() should never be called.\u003c/p\u003e","function_template":"function [] = counting_loop(N)\r\n  for ???\r\nend\r\n\r\nfunction mydisplay(v)\r\n  global gRV ;\r\n  gRV(end+1) = v ;\r\nend ","test_suite":"%%\r\nglobal gRV;\r\ngRV = [];\r\nN   = 10;\r\ngRV_correct = [3 5 7 9];\r\ncounting_loop(N);\r\ncode = textread('counting_loop.m', '%s');\r\nassert(isequal(gRV, gRV_correct) \u0026\u0026 strcmp(code(5), 'for'));\r\n%%\r\nglobal gRV;\r\ngRV = [];\r\nN   = 5;\r\ngRV_correct = [3 5];\r\ncounting_loop(N);\r\ncode = textread('counting_loop.m', '%s');\r\nassert(isequal(gRV, gRV_correct) \u0026\u0026 strcmp(code(5), 'for'));\r\n%%\r\nglobal gRV;\r\ngRV = [];\r\nN   = 3;\r\ngRV_correct = [3];\r\ncounting_loop(N);\r\ncode = textread('counting_loop.m', '%s');\r\nassert(isequal(gRV, gRV_correct) \u0026\u0026 strcmp(code(5), 'for'));\r\n%%\r\nglobal gRV;\r\ngRV = [];\r\nN   = 0;\r\ngRV_correct = [];\r\ncounting_loop(N);\r\ncode = textread('counting_loop.m', '%s');\r\nassert(isequal(gRV, gRV_correct) \u0026\u0026 strcmp(code(5), 'for'));\r\n%%\r\nglobal gRV;\r\ngRV = [];\r\nN   = 39;\r\ngRV_correct = [3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39];\r\ncounting_loop(N);\r\ncode = textread('counting_loop.m', '%s');\r\nassert(isequal(gRV, gRV_correct) \u0026\u0026 strcmp(code(5), 'for'));","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":24594,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":60,"test_suite_updated_at":"2014-09-30T07:12:50.000Z","rescore_all_solutions":false,"group_id":1,"created_at":"2014-09-29T06:04:35.000Z","updated_at":"2026-03-06T11:34:21.000Z","published_at":"2014-09-30T07:12:50.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eComplete the function below using a for loop to count from 3 to N by 2. For example, if N is 10, count 3, 5, 7, 9 and stop. For each value v, call the function mydisplay(v). Note that N could be less than 3, in which case mydisplay() should never be called.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"term":"tag:\"cs109\"","current_player_id":null,"fields":[{"name":"page","type":"integer","callback":null,"default":1,"directive":null,"facet":null,"facet_method":"and","operator":null,"param":null,"static":null,"prepend":true},{"name":"per_page","type":"integer","callback":null,"default":50,"directive":null,"facet":null,"facet_method":"and","operator":null,"param":null,"static":null,"prepend":true},{"name":"sort","type":"string","callback":null,"default":null,"directive":null,"facet":null,"facet_method":"and","operator":null,"param":null,"static":null,"prepend":true},{"name":"body","type":"text","callback":null,"default":"*:*","directive":null,"facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":false},{"name":"group","type":"string","callback":null,"default":null,"directive":"group","facet":true,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"difficulty_rating_bin","type":"string","callback":null,"default":null,"directive":"difficulty_rating_bin","facet":true,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"id","type":"integer","callback":null,"default":null,"directive":"id","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"tag","type":"string","callback":null,"default":null,"directive":"tag","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"product","type":"string","callback":null,"default":null,"directive":"product","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"created_at","type":"timeframe","callback":{},"default":null,"directive":"created_at","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"profile_id","type":"integer","callback":null,"default":null,"directive":"author_id","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"created_by","type":"string","callback":null,"default":null,"directive":"author","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"player_id","type":"integer","callback":null,"default":null,"directive":"solver_id","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"player","type":"string","callback":null,"default":null,"directive":"solver","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"solvers_count","type":"integer","callback":null,"default":null,"directive":"solvers_count","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"comments_count","type":"integer","callback":null,"default":null,"directive":"comments_count","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"likes_count","type":"integer","callback":null,"default":null,"directive":"likes_count","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"leader_id","type":"integer","callback":null,"default":null,"directive":"leader_id","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true},{"name":"leading_solution","type":"integer","callback":null,"default":null,"directive":"leading_solution","facet":null,"facet_method":"and","operator":null,"param":"term","static":null,"prepend":true}],"filters":[{"name":"asset_type","type":"string","callback":null,"default":null,"directive":null,"facet":null,"facet_method":"and","operator":null,"param":null,"static":"\"cody:problem\"","prepend":true},{"name":"profile_id","type":"integer","callback":{},"default":null,"directive":null,"facet":null,"facet_method":"and","operator":null,"param":"author_id","static":null,"prepend":true}],"query":{"params":{"per_page":50,"term":"tag:\"cs109\"","current_player":null,"sort":"map(difficulty_value,0,0,999) asc"},"parser":"MathWorks::Search::Solr::QueryParser","directives":{"term":{"directives":{"tag":[["tag:\"cs109\"","","\"","cs109","\""]]}}},"facets":{"#\u003cMathWorks::Search::Field:0x00007f74ab86dd60\u003e":null,"#\u003cMathWorks::Search::Field:0x00007f74ab86dcc0\u003e":null},"filters":{"#\u003cMathWorks::Search::Field:0x00007f74ab86d400\u003e":"\"cody:problem\""},"fields":{"#\u003cMathWorks::Search::Field:0x00007f74ab86dfe0\u003e":1,"#\u003cMathWorks::Search::Field:0x00007f74ab86df40\u003e":50,"#\u003cMathWorks::Search::Field:0x00007f74ab86dea0\u003e":"map(difficulty_value,0,0,999) asc","#\u003cMathWorks::Search::Field:0x00007f74ab86de00\u003e":"tag:\"cs109\""},"user_query":{"#\u003cMathWorks::Search::Field:0x00007f74ab86de00\u003e":"tag:\"cs109\""},"queried_facets":{}},"query_backend":{"connection":{"configuration":{"index_url":"http://index-op-v2/solr/","query_url":"http://search-op-v2/solr/","direct_access_index_urls":["http://index-op-v2/solr/"],"direct_access_query_urls":["http://search-op-v2/solr/"],"timeout":10,"vhost":"search","exchange":"search.topic","heartbeat":30,"pre_index_mode":false,"host":"rabbitmq-eks","port":5672,"username":"search","password":"J3bGPZzQ7asjJcCk","virtual_host":"search","indexer":"amqp","http_logging":"true","core":"cody"},"query_connection":{"uri":"http://search-op-v2/solr/cody/","proxy":null,"connection":{"parallel_manager":null,"headers":{"User-Agent":"Faraday v1.0.1"},"params":{},"options":{"params_encoder":"Faraday::FlatParamsEncoder","proxy":null,"bind":null,"timeout":null,"open_timeout":null,"read_timeout":null,"write_timeout":null,"boundary":null,"oauth":null,"context":null,"on_data":null},"ssl":{"verify":true,"ca_file":null,"ca_path":null,"verify_mode":null,"cert_store":null,"client_cert":null,"client_key":null,"certificate":null,"private_key":null,"verify_depth":null,"version":null,"min_version":null,"max_version":null},"default_parallel_manager":null,"builder":{"adapter":{"name":"Faraday::Adapter::NetHttp","args":[],"block":null},"handlers":[{"name":"Faraday::Response::RaiseError","args":[],"block":null}],"app":{"app":{"ssl_cert_store":{"verify_callback":null,"error":null,"error_string":null,"chain":null,"time":null},"app":{},"connection_options":{},"config_block":null}}},"url_prefix":"http://search-op-v2/solr/cody/","manual_proxy":false,"proxy":null},"update_format":"RSolr::JSON::Generator","update_path":"update","options":{"url":"http://search-op-v2/solr/cody"}}},"query":{"params":{"per_page":50,"term":"tag:\"cs109\"","current_player":null,"sort":"map(difficulty_value,0,0,999) asc"},"parser":"MathWorks::Search::Solr::QueryParser","directives":{"term":{"directives":{"tag":[["tag:\"cs109\"","","\"","cs109","\""]]}}},"facets":{"#\u003cMathWorks::Search::Field:0x00007f74ab86dd60\u003e":null,"#\u003cMathWorks::Search::Field:0x00007f74ab86dcc0\u003e":null},"filters":{"#\u003cMathWorks::Search::Field:0x00007f74ab86d400\u003e":"\"cody:problem\""},"fields":{"#\u003cMathWorks::Search::Field:0x00007f74ab86dfe0\u003e":1,"#\u003cMathWorks::Search::Field:0x00007f74ab86df40\u003e":50,"#\u003cMathWorks::Search::Field:0x00007f74ab86dea0\u003e":"map(difficulty_value,0,0,999) asc","#\u003cMathWorks::Search::Field:0x00007f74ab86de00\u003e":"tag:\"cs109\""},"user_query":{"#\u003cMathWorks::Search::Field:0x00007f74ab86de00\u003e":"tag:\"cs109\""},"queried_facets":{}},"options":{"fields":["id","difficulty_rating"]},"join":" "},"results":[{"id":2389,"difficulty_rating":"easy"},{"id":2509,"difficulty_rating":"easy"},{"id":2510,"difficulty_rating":"easy"},{"id":2609,"difficulty_rating":"easy"},{"id":2529,"difficulty_rating":"easy"},{"id":2530,"difficulty_rating":"easy-medium"},{"id":2610,"difficulty_rating":"easy-medium"}]}}