Problem 44500. Find the starting index of a consecutive condition

Solution 1418255

Submitted on 16 Jan 2018 by Michael

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Test	Status	Code Input and Output
1	Pass	v = logical([0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]); n = 1; i = consecutiveFind(v, n); i_correct = 2; assert(isequal(i, i_correct))
2	Pass	v = logical([0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]); n = 4; i = consecutiveFind(v, n); i_correct = 6; assert(isequal(i, i_correct))
3	Pass	v = logical([0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]); n = 6; i = consecutiveFind(v, n); assert(isempty(i))
4	Pass	v = false(1, 10); n = 1; i = consecutiveFind(v, n); assert(isempty(i))
5	Pass	x = 0 : pi/4 : 2*pi; v = sin(x) < 1; n = 5; i = consecutiveFind(v, n); i_correct = 4; assert(isequal(i, i_correct))