Cody

# Problem 43601. Find the sines of an isosceles triangle when given its area and height

Solution 1038555

Submitted on 30 Oct 2016 by Peng Liu
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### Test Suite

Test Status Code Input and Output
1   Pass
A = 60; h = 5; y_correct = [0.3752 0.3752 0.9623]; tolerance = 1e-4; y = theSineOfAnglesOfATriangle(A,h); assert(abs(y(1)-y_correct(1))<tolerance) assert(abs(y(2)-y_correct(2))<tolerance) assert(abs(y(3)-y_correct(3))<tolerance)

2   Pass
A = 12; h = 4; y_correct = [0.7174 0.7174 0.9320]; tolerance = 1e-4; y = theSineOfAnglesOfATriangle(A,h); assert(abs(y(1)-y_correct(1))<tolerance) assert(abs(y(2)-y_correct(2))<tolerance) assert(abs(y(3)-y_correct(3))<tolerance)

3   Pass
A = 120; h = 8; y_correct = [0.4534 0.4534 0.9813]; tolerance = 1e-4; y = theSineOfAnglesOfATriangle(A,h); assert(abs(y(1)-y_correct(1))<tolerance) assert(abs(y(2)-y_correct(2))<tolerance) assert(abs(y(3)-y_correct(3))<tolerance)

4   Pass
A = 11; h = 7; y_correct = [0.828103613613504 0.828103613613504 0.424198555538884]; tolerance = 1e-4; y = theSineOfAnglesOfATriangle(A,h); assert(abs(y(1)-y_correct(1))<tolerance) assert(abs(y(2)-y_correct(2))<tolerance) assert(abs(y(3)-y_correct(3))<tolerance)

5   Pass
A = 10; h = pi; y_correct = [0.646090546283235 0.646090546283235 0.989166179104111]; tolerance = 1e-4; y = theSineOfAnglesOfATriangle(A,h); assert(abs(y(1)-y_correct(1))<tolerance) assert(abs(y(2)-y_correct(2))<tolerance) assert(abs(y(3)-y_correct(3))<tolerance)

6   Pass
A = 100; h = 90; y_correct = [0.841429811769772 0.841429811769772 0.0246869683113754]; tolerance = 1e-4; y = theSineOfAnglesOfATriangle(A,h); assert(abs(y(1)-y_correct(1))<tolerance) assert(abs(y(2)-y_correct(2))<tolerance) assert(abs(y(3)-y_correct(3))<tolerance)