Cody

# Problem 38. Return a list sorted by number of occurrences

Solution 1807830

Submitted on 6 May 2019 by Rajpurohith Urmila
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### Test Suite

Test Status Code Input and Output
1   Pass
x = [1 2 2 2 3 3 7 7 93] y_correct = [2 3 7 1 93]; assert(isequal(popularity(x),y_correct))

x = 1 2 2 2 3 3 7 7 93 m = [] y = [] c = 1 m = 1 c = 3 m = 1 3 c = 3 m = 1 3 3 c = 3 m = 1 3 3 3 c = 2 m = 1 3 3 3 2 c = 2 m = 1 3 3 3 2 2 c = 2 m = 1 3 3 3 2 2 2 c = 2 m = 1 3 3 3 2 2 2 2 c = 1 m = 1 3 3 3 2 2 2 2 1 p = 1 2 3 7 93 q = 1 2 5 7 9 f = 1 3 2 2 1 j = 3 2 2 1 1 k = 2 3 4 1 5 l = 2 3 4 1 5 o = 2 y = 2 o = 3 y = 2 3 o = 7 y = 2 3 7 o = 1 y = 2 3 7 1 o = 93 y = 2 3 7 1 93

2   Pass
x = [-1 19 20 -1 -1 87 19 34 19 -1 21 87 20 10 20 34 19 -1]; y_correct = [-1 19 20 34 87 10 21]; assert(isequal(popularity(x),y_correct))

m = [] y = [] c = 5 m = 5 c = 4 m = 5 4 c = 3 m = 5 4 3 c = 5 m = 5 4 3 5 c = 5 m = 5 4 3 5 5 c = 2 m = 5 4 3 5 5 2 c = 4 m = 5 4 3 5 5 2 4 c = 2 m = 5 4 3 5 5 2 4 2 c = 4 m = 5 4 3 5 5 2 4 2 4 c = 5 m = 5 4 3 5 5 2 4 2 4 5 c = 1 m = 5 4 3 5 5 2 4 2 4 5 1 c = 2 m = 5 4 3 5 5 2 4 2 4 5 1 2 c = 3 m = 5 4 3 5 5 2 4 2 4 5 1 2 3 c = 1 m = 5 4 3 5 5 2 4 2 4 5 1 2 3 1 c = 3 m = 5 4 3 5 5 2 4 2 4 5 1 2 3 1 3 c = 2 m = 5 4 3 5 5 2 4 2 4 5 1 2 3 1 3 2 c = 4 m = 5 4 3 5 5 2 4 2 4 5 1 2 3 1 3 2 4 c = 5 m = 5 4 3 5 5 2 4 2 4 5 1 2 3 1 3 2 4 5 p = -1 10 19 20 21 34 87 q = 1 14 2 3 11 8 6 f = 5 1 4 3 1 2 2 j = 5 4 3 2 2 1 1 k = 1 3 4 6 7 2 5 l = 1 3 4 6 7 2 5 o = -1 y = -1 o = 19 y = -1 19 o = 20 y = -1 19 20 o = 34 y = -1 19 20 34 o = 87 y = -1 19 20 34 87 o = 10 y = -1 19 20 34 87 10 o = 21 y = -1 19 20 34 87 10 21