Problem 385. Poker Series 09: IsHighCard

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Solution 48825

Submitted on 22 Feb 2012 by Alfonso Nieto-Castanon

Size: 52
Leading solution size is 48.

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6 Comments

6 Comments

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Peng Liu on 6 Dec 2015

This solution doesn't work on R2015a or R2015b. It seems that the behavior of circshift is changed. For example, circshift(sparse(logical([1 2 3])),[0 1]) on R2015b returns all zeros.

Jan Orwat on 6 Dec 2015

Hi Peng, it seems that last major changes to circshift were introduced in 2014a (dim selection added). I'm not able to check this version, 2015a also returns falses. Anyway, (not) nice bug :).

Peng Liu on 7 Dec 2015

Hi Jan, I don't have 2014a either. But I was able to check with 2013a available here: http://anycodes.cn (On the left hand side, you can select to run MATLAB). While circshift(sparse(logical([1 2 3])),[0 1]) and circshift(sparse(+logical([1 2 3])),[0 1]) produce different output on 2015a and 2015b, they give the same result (up to a class difference) on 2013a.

Jan Orwat on 8 Dec 2015

It's definitely a bug. It seems the newest version of circshift doesn't handle sparse logical matrices properly. It somehow changes trues to falses, but treat them like nonzeros. This leads to some funny logical properties because of the way the algorithms for sparse matrices work. Check following code: A = circshift(sparse([false false true false true]),[0 1]); A, nonzeros(A); full(A), A|1, A&1, ~A, xor(A,1), xor(A,0), and(A,A), or(A,A), A==~~A, isequal(A,~~A), isequal(A|0,A), %(etc.);
B = sparse([false false true false true]); B, B = B([end 1:end-1]), ...

Jan Orwat on 8 Dec 2015

This is my favourite:
C = circshift(sparse(true),1);

Peng Liu on 8 Dec 2015

Haha, this is definitely a funny example to elaborate on the improper behavior of circshift/sparse when dealing with sparse logical matrix. I agree with you this is a bug, but still not very sure the bug is due to circshift or sparse. Maybe somebody can report this bug to MATHWORKS...

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Problem 385. Poker Series 09: IsHighCard

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