How to loop an already looping code, in order to find output convergent value.

조회 수: 1 (최근 30일)
%I have code which includes a for and while loop which I have to loop one
%million times, to find a convergent output (probability).
sq=0;
i=1;
while sq<=250
sq(i)=i^2
i=i+1;
end
prime=primes(250)
pos=randi(255,1,1)
position=pos;
for f=2:15
r=randi(2,1,1);
if (position(f-1)==1)
position(f)=2;
elseif (position(f-1)==250)
position(f)=249;
elseif (r==1)
position(f)=position(f-1)+1;
else
position(f)=position(f-1)-1;
end
end
disp('Position = ');
disp(position);
plot(1:length(position),position)
xlabel('time')
ylabel('Position')
probability=abs(pos-position(length(position)))/15*100
%how do I make this entire code, that calculates for a number loop one
%million times and give the final convergent number.

채택된 답변

Walter Roberson
Walter Roberson 2021년 7월 19일
The system does not converge.
%I have code which includes a for and while loop which I have to loop one
%million times, to find a convergent output (probability).
iter = 1e3;
probability = zeros(1,iter);
N = 250;
sq = (1:N).^2;
prime = primes(N);
for K = 1 : iter
pos = randi(255,1,1);
position = zeros(1,15);
position(1) = pos;
for f=2:15
r=randi(2,1,1);
if (position(f-1)==1)
position(f)=2;
elseif (position(f-1)==250)
position(f)=249;
elseif (r==1)
position(f)=position(f-1)+1;
else
position(f)=position(f-1)-1;
end
end
% disp('Position = ');
% disp(position);
plot(position)
hold on
xlabel('time')
ylabel('Position')
probability(K) = abs(pos-position(end))/15*100;
end
%how do I make this entire code, that calculates for a number loop one
%million times and give the final convergent number.
probability(end-5:end)
ans = 1×6
0 53.3333 0 0 0 40.0000

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by