Dimensions of arrays being concatenated are not consistent.

Hello, attached is my code and actually the code works, but after a few rounds in for an error message appears.

''Dimensions of arrays being concatenated are not consistent.''

function w=deformation(x,y,z,H,curv,R,meshlense)% x,y,z are the tool reference positions  ztool is the shape of the tool (where the curvature is inputed) R is the radius of the tool
    %x=feed*cos(theta)// or as x y input
    %y=feed*sin(theta)
  
    
    T=[1 0 0 -x; 0 1 0 -y; 0 0 -1 z; 0 0 0 1];%transformation matrix lense to tool
    %0 1 0 -y;...
    %0 0 -1 z;...
    %0 0 0 1];
    
    step=meshlense.x(2)-meshlense.x(1);
    [n,m]=size(meshlense.z);
    w.z=zeros(n,m);
    w.t=zeros(n,m);
    
    for i=1:1:n % to sweep over the tool
        for j=1:1:m % condition to be on tool and on lense comparing Radius of lense then Radius of tool
            if (((n-1)*step/2)^2-((j-1)*step+meshlense.y(1))^2-((i-1)*step+meshlense.x(1))^2)>0 && (R^2-(y-((j-1)*step+meshlense.y(1)))^2-(x-((i-1)*step+meshlense.x(1)))^2)>0 
               i
               j
                Behzad = [meshlense.x(i);meshlense.y(j);meshlense.z(i,j); 1] ;
                toolref=T*Behzad;
                deltaz=toolref(3)-ztool(meshlense.x(i),meshlense.y(j),curv,2*R);
                w.z(i,j)=H-deltaz; % to find the deformation at point x,y by calculating the heght between hard plastic and lense then comparing with original height
               if deltaz<0 
                    w.t(i,j)=0; % plastic of tool passes thru the lense; wenn deltaz<0, dann sitzt Linse direkt auf Werkzeug auf w.t = 0
                elseif w.z(i,j)<0 %Wenn w.z <0 dann findet keine Berührung statt , denn das Werkzeug ist angehoben 
                    w.z(i,j)=0; % if tool is lifted
                    w.t(i,j)=4;
                else
                    w.t(i,j)=1; % there is normal deformation, ansonsten ist normale Deformation 
                end
            elseif (((n-1)*step/2)^2-((j-1)*step+meshlense.y(1))^2-((i-1)*step+meshlense.x(1))^2)<0 
                if (R^2-(y-((j-1)*step+meshlense.y(1)))^2-(x-((i-1)*step+meshlense.x(1)))^2)>0 
                    w.t(i,j)=2; % is off lense and on tool
                else
                    w.t(i,j)=3; % is off lense but off tool
                end
            else
                w.t(i,j)=-1; % is on lense but off tool
            end
        end
    end

[Jan]

Please post the complete error message. It tells us, where the error occurs. Sharing this important information makes it much easier to help you.

A concatenation happens only here:

[meshlense.x(i);meshlense.y(j);meshlense.z(i,j); 1]

I cannot see, how this could fail with the shown message.

[farzad jalizi]

Thanks for your attention.

Error:

Error using vertcat

Dimensions of arrays being concatenated are not consistent.

Error in deformation (line 7)

T=[1 0 0 -x; 0 1 0 -y; 0 0 1 -z; 0 0 0 0];%transformation matrix lense to tool

[Mathieu NOE]

seems to me x,y,z should always be scalar , which may not be true after a few rounds

check dimensions during the iterations...

Answer 1

[Jan]

Use the debugger to check your code:

dbstop if error

Start your program after typing this in the command window. When Matlab stops, check the sizes of x, y, z:

size(x)
size(y)
size(z)