Find the index of the element of a cell array which has the maximum size

I have a cell array (B) which has elements having two columns and different number of rows. I want to find the element which has the largest number of rows. I wrote the following code which seems to me non-professional. Is there a better way to do that?

    max_index=0;
    max_size=0;
    for i=1:numel(B)
        if max_size<size(B{i},1)
            max_size=size(B{i},1);
            max_index=i;
        end
    end

Thanks.

Answer 1

[Jan]

[max_size, max_index] = max(cellfun('size', B, 1))

[huahua]

What if I want the cell of second largest size?

[Jan]

@huahua:

siz      = cellfun('size', B, 1);
[~, idx] = max(siz);
siz(idx) = -Inf;
[size2, index2] = max(siz);

This is cheaper than sorting.

Answer 2

[Jos (10584)]

NrowsB = cellfun('size',B,1) ;
[~, ri] = sort(NrowsB)
ri(k) % index of B with the k-th most number of rows