Given a linear system i want to do Gauss-Seidel iteration.But getting error.Would appreciate if anyone fix me the code. Thanks.

조회 수: 5(최근 30일)
Abid Shahriar
Abid Shahriar 2021년 5월 30일
편집: KALYAN ACHARJYA 2021년 5월 30일
>> x(1)=1.5;
>> y(1)=-1;
>> z(1)=1;
>> iter(1)=0;
>> for n=1:4
iter(n+1)=n;
x(n+1)=(16+3*y(n)-2*z(n))/8;
y(n+1)=(-9+2*x(n+1)-z(n))/8;
z(n+1)=(1+2*x(n+1)-4*y(n+1))/10;
end
>> Solution = [iter',x',y',z’]

답변(1개)

KALYAN ACHARJYA
KALYAN ACHARJYA 2021년 5월 30일
No coding syntax error
x(1)=1.5;
y(1)=-1;
z(1)=1;
iter(1)=0;
for n=1:4
iter(n+1)=n;
x(n+1)=(16+3*y(n)-2*z(n))/8;
y(n+1)=(-9+2*x(n+1)-z(n))/8;
z(n+1)=(1+2*x(n+1)-4*y(n+1))/10;
end
Solution = [iter',x',y',z']
Result:
Solution =
0 1.5 -1 1
1 1.375 -0.90625 0.7375
2 1.4758 -0.84824 0.73445
3 1.4983 -0.84223 0.73655
4 1.5 -0.84206 0.73683
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KALYAN ACHARJYA
KALYAN ACHARJYA 2021년 5월 30일
Can you delete the z' (transpose sign) & type it again?
Note on the z' (superscript sign)

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