MATLAB Answers

Linear Label on Logarithmic Plot

조회 수: 3(최근 30일)
Douglas Anderson
Douglas Anderson 2021년 5월 13일
편집: Walter Roberson 2021년 5월 14일
Hello!
I have an "example" regression loglog graph to show someone. The Y axis is not very large, but is less than 1, so it shows up as log rather than linear.
Is there a way to do this cleanly? Here's the code:
% reggie
rng('shuffle');
Intercept = 1000;
Slope = -1.6;
dist = 150:50:300;
vib = Intercept*(dist.^Slope);
minx = 50;
maxx = 400;
figure
loglog(dist,vib,'o','MarkerFaceColor','r')
xlim([minx maxx])
ylim([0.05 1])
hold on
grid on
grid minor
loglog([minx maxx],[Intercept*(minx^Slope) Intercept*(maxx^Slope)],'--');
xlabel('Distance (ft)');
ylabel('Vibration (in/s)');
title('Regression Example');
for n = 1:length(dist)
scatterling = 0.3 * vib(n);
median_value = vib(n);
new_values = scatterling.*randn(6,1)+median_value;
loglog(dist(n),new_values,'diamond','LineStyle','none');
end
newdist = 100;
reduction_factor = 0.65;
newvib = (reduction_factor * Intercept) *(newdist.^Slope);
loglog(newdist,newvib,'o','MarkerFaceColor','b');
scatterling = 0.4 * newvib;
median_value = newvib;
new_values = scatterling.*randn(6,1)+median_value;
loglog(newdist,new_values,'diamond','LineStyle','none','MarkerFaceColor','g');
Thanks!
Doug
  댓글 수: 2
Douglas Anderson
Douglas Anderson 2021년 5월 14일
Thank you Walter.
I would like the scale to be logarithmic, but the label to be linear. For this case, it's basically from 0.05 to 1.0. So there wouldn't be a lot of points, but as it is, I get two labels: 10 superscript -1 and 10 superscript 0.
Thanks!
Doug

댓글을 달려면 로그인하십시오.

채택된 답변

Walter Roberson
Walter Roberson 2021년 5월 14일
ax = gca;
ax.YAxis.Exponent = 0;
  댓글 수: 2
Walter Roberson
Walter Roberson 2021년 5월 14일
% reggie
rng('shuffle');
Intercept = 1000;
Slope = -1.6;
dist = 150:50:300;
vib = Intercept*(dist.^Slope);
minx = 50;
maxx = 400;
figure
loglog(dist,vib,'o','MarkerFaceColor','r')
xlim([minx maxx])
ylim([0.05 1])
hold on
grid on
grid minor
loglog([minx maxx],[Intercept*(minx^Slope) Intercept*(maxx^Slope)],'--');
xlabel('Distance (ft)');
ylabel('Vibration (in/s)');
title('Regression Example');
for n = 1:length(dist)
scatterling = 0.3 * vib(n);
median_value = vib(n);
new_values = scatterling.*randn(6,1)+median_value;
loglog(dist(n),new_values,'diamond','LineStyle','none');
end
newdist = 100;
reduction_factor = 0.65;
newvib = (reduction_factor * Intercept) *(newdist.^Slope);
loglog(newdist,newvib,'o','MarkerFaceColor','b');
scatterling = 0.4 * newvib;
median_value = newvib;
new_values = scatterling.*randn(6,1)+median_value;
loglog(newdist,new_values,'diamond','LineStyle','none','MarkerFaceColor','g');
yticklabels(compose("%g", yticks))

댓글을 달려면 로그인하십시오.

추가 답변(0개)

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by