# How to replace all zeros in a matrix with a vector from 1 to 9 in the order of ascending indices?

조회 수: 3(최근 30일)
Hearthy Tampol 2021년 5월 13일
댓글: Image Analyst 2021년 5월 14일
I have a matrix x
x =
0 4 9 9 -4 0
4 0 -3 -3 -1 0
0 0 9 9 3 -2
0 0 5 5 10 0
-3 9 -4 -4 10 9
0 0 -1 8 5 0
How can I replace all zeros with values 1 to 9 in the order of ascending indices?
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Hearthy Tampol 2021년 5월 14일
Yes this is homework. I now realized where I lost it haha, there are elements that I incorrectly typed, my bad. But, thanks for the code, I was able to manipulate it to get the right answer I need. Thanks!!

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### 채택된 답변

Image Analyst 2021년 5월 13일
Try this. The replacements are in "column-major" order, since that's how MATLAB does things.
x = [
0 4 9 9 -4 0
4 0 -3 -3 -1 0
0 0 9 9 3 -2
0 0 5 5 10 0
-3 9 -4 -4 10 9
0 0 -1 8 5 0]
zeroMap = x == 0
numZeros = sum(zeroMap(:))
x(zeroMap) = 1 : numZeros
----------------------------------------------------------------------------------
x =
0 4 9 9 -4 0
4 0 -3 -3 -1 0
0 0 9 9 3 -2
0 0 5 5 10 0
-3 9 -4 -4 10 9
0 0 -1 8 5 0
zeroMap =
6×6 logical array
1 0 0 0 0 1
0 1 0 0 0 1
1 1 0 0 0 0
1 1 0 0 0 1
0 0 0 0 0 0
1 1 0 0 0 1
numZeros =
12
x =
1 4 9 9 -4 9
4 5 -3 -3 -1 10
2 6 9 9 3 -2
3 7 5 5 10 11
-3 9 -4 -4 10 9
4 8 -1 8 5 12
If, instead of 1-12, you want to go from 1-9 and then from 1-3, you can do this:
x = [
0 4 9 9 -4 0
4 0 -3 -3 -1 0
0 0 9 9 3 -2
0 0 5 5 10 0
-3 9 -4 -4 10 9
0 0 -1 8 5 0]
zeroMap = x == 0
numZeros = sum(zeroMap(:))
v = rem(0 : numZeros-1, 9) + 1
x(zeroMap) = v
v =
1 2 3 4 5 6 7 8 9 1 2 3
x =
1 4 9 9 -4 9
4 5 -3 -3 -1 1
2 6 9 9 3 -2
3 7 5 5 10 2
-3 9 -4 -4 10 9
4 8 -1 8 5 3
##### 댓글 수: 4표시숨기기 이전 댓글 수: 3
Image Analyst 2021년 5월 14일
You're welcome. (Thanks for Accepting the answer to award reputation points.)
Tip: Did you know that you can click the double-page icon in the upper right corner of code sections to copy the code into the clipboard, then you can paste it into MATLAB editor window from the clipboard.

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R2021a

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