Assign the file name and path to a variable from a file open window

조회 수: 6 (최근 30일)
In my code, I open a csv file and then parse the data with importdata. I am trying to find a way to not have to hard code the file name and path of the csv and instead use a dialog box to select the file. I have tried to use uiopen but that will not return the full filename to a var.
Right now I have:
fname = 'C:\path\file.csv';
delim = ',';
indata = importdata(fname, delim);
I'd like to make it easier by assigning fname to a file selected via a file open window. Something like:
fname = opendiag('*.csv');
Where after selecting the file it's full name and path gets assigned to the var which can then be used with importdata.

채택된 답변

Jason Burke
Jason Burke 2021년 4월 8일
I found uigetfile.
[file, path] = uigetfile('*.csv');
fname = fullfile(path,file);

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Develop uifigure-Based Apps에 대해 자세히 알아보기

태그

제품


릴리스

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by