Unable to perform assignment because the left and right sides have a different number of element

조회 수: 1 (최근 30일)
hey
im new to matlab and i have problem i dont find how i can Increases the array size in a loop
i have tryed to use ones without succses
i will explain my code :
i have 6 game cube (1:6) and i have to throw all of them
i have to display all possible option which i did with sucsess i dont know if its the best option
but i also need to display all result that equal to 20 or bigger then 30 - here i need help
here is my code so far :
dbstop if error
cube=[1 2 3 4 5 6];
A=zeros(6^6,6); % number of the option
K=zeros(s,6);
L=zeros(s,6);
s=numel(A);
b20=0; % throwing cube ==20
b30=0; %;throwing cube >30
n=0; % counter
m=0; % counter
for i1=1:6
for i2=1:6
for i3=1:6
for i4=1:6
for i5=1:6
for i6=1:6
A=[i1 i2 i3 i4 i5 i6];
disp(A);
if (i1+i2+i3+i4+i5+i6)==20
b20=b20+1;
n=n+1;
K(n)=A;
elseif (i1+i2+i3+i4+i5+i6)>30
b30=b30+1;
m=m+1;
L(n)=A;
end
end
end
end
end
end
end
i will appriciate any help and improvment to my code

채택된 답변

Jan
Jan 2021년 3월 22일
편집: Jan 2021년 3월 22일
K(n, :) = A;
% ^
L(n, :) = A;
% ^
The vector A can be assigne to the vector of the array K and L only. K(n) is a scalar, the same as K(n, 1).
Another problem:
K=zeros(s,6); % s is used
L=zeros(s,6);
s=numel(A); % but defined later only.
% But you do not need numal(A) outputs, but size(A, 1) only
Pre-allocating A by "A=zeros(6^6,6);" is not needed, if you overwrite it in the code:
A=[i1 i2 i3 i4 i5 i6];
The variable n and b20 as well as m and b30 have the same values. To you can omit n and m, or b20 and b30.
The variable cube is not used anywhere. So you can omit the line "cube=[1 2 3 4 5 6];"
  댓글 수: 4
the cyclist
the cyclist 2021년 3월 25일
I was thinking of an array where n is larger than size(K,1), for example:
n = 5;
K = rand(3,6);
K(n) % Correct linear indexing
ans = 0.5661
K(n,1) % Error with subscript indexing
Index in position 1 exceeds array bounds (must not exceed 3).
Jan
Jan 2021년 3월 25일
Yes, now I understand your comment. Thanks for the explanation. Sometimes experiences block my view on trivial bugs, because I would avoid them intuitively.

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추가 답변 (1개)

the cyclist
the cyclist 2021년 3월 22일
You need to use
K(n,:)=A;
and
L(n,:)=A;
to assign the row vector A to a row of K or L.
K(n) is a single element, using linear indexing.

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