How to test a value before adding it to the matrix

Hi

In the code below, an matrix named allma contains some duplicate values

The question is what modifications must be added to make the array's values non-duplicate and the size of the matrix is 16 * 16

clear all;clc;

%create the first quadrant of matrix

r=0.2;x(1,1)=0.8;

for i=2:64

x(i)=r+(1-x(i-1))^2;%The first equation

end

A=x;

for i=1: 64

ZA=A(i);

ssA(i)=round(mod(ZA*10^5,256));%To make the values integer between 0 - 255

end

A1=reshape(ssA,8,[]);

for i=1:8

for j=1:8

allma(i,j)=A1(i,j);%Add the values to the large matrix to represent the first quadrant

end

end

%create the second quadrant of matrix

u1=0.15;u2=0.13;Y(1)=0.2; X(1)=0.6;m1=2.76;m2=3.45;n=15;

for i=1:63

X(i+1)=m1*x(i)*(1-x(i))+u1*Y(i)^2;%The second equation

Y(i+1)=m2*Y(i)*(1-Y(i))+u2*((X(i)^2)+X(i)*Y(i));

end

B=X;

for i=1: 64

ZB=B(i);

ssB(i)=round(mod(ZB*10^5,256));%To make the values integer between 0 - 255

end

B1=reshape(ssB,8,[]);

ii=1;

for i=9:16

jj=1;

for j=1:8

allma(i,j)=B1(ii,jj);%Add the values to the large matrix to represent the second quadrant

jj=jj+1;

end

ii=ii+1;

end

%%create the third quadrant of matrix

r = 28; b = 8/3;

yy(1) = 20; z0(1) = 30; Q=10;

for i=2:64

X3d(i)=Q*(Y(i-1)-X(i-1));%The thied equation

yy(i)=r*X(i-1)-yy(i-1)-X(i-1)*z0(i-1);

z0(i)=X(i-1)*yy(i-1)+b*z0(i-1);%The fourth equation

end

C=X3d;

for i=1: 64

ZC=X3d(i);

ssC(i)=round(mod(ZC*10^5,256));%To make the values integer between 0 - 255

end

C1=reshape(ssC,8,[]);

ii=1;

for i=1:8

jj=1;

for j=9:16

allma(i,j)=C1(ii,jj);%Add the values to the large matrix to represent the third quadrant

jj=jj+1;

end

ii=ii+1;

end

%%create the fourth quadrant of matrix

D=z0;

for i=1: 64

ZD=z0(i);

ssD(i)=round(mod(ZD*10^5,256));%To make the values integer between 0 - 255

end

D1=reshape(ssD,8,[]);

ii=1;

for i=9:16

jj=1;

for j=9:16

allma(i,j)=D1(ii,jj);%Add the values to the large matrix to represent the fourth quadrant

jj=jj+1;

end

ii=ii+1;

end

allma =

128 151 252 249 49 224 191 178 0 39 95 255 36 123 157 237

192 60 40 63 172 217 235 242 128 56 46 121 250 175 96 198

192 145 73 180 21 213 187 176 144 37 217 220 154 126 179 44

114 69 136 100 187 223 237 243 121 132 231 242 118 100 44 156

43 11 190 126 255 204 183 175 211 135 164 64 38 55 52 159

2 16 212 130 200 228 239 244 8 183 44 39 63 22 28 161

86 225 80 83 238 197 180 173 66 77 256 125 22 166 146 196

220 174 15 154 209 232 241 245 83 162 166 108 48 116 194 115

96 7 22 171 155 111 225 237 192 37 210 36 0 0 0 0

216 65 140 217 91 156 150 41 128 157 194 160 0 0 0 0

197 71 113 3 232 161 106 253 165 75 250 64 0 0 0 0

188 35 135 128 198 169 228 78 5 252 165 128 0 0 0 0

224 8 93 230 254 17 248 14 172 69 30 0 0 0 0 0

193 184 99 152 2 234 140 132 159 130 41 0 0 0 0 0

124 23 91 201 29 213 202 215 169 38 138 0 0 0 0 0

70 71 49 112 72 153 195 59 179 87 80 0 0 0 0 0

[KALYAN ACHARJYA]

Please redesign the question with sample example. You can iterate the loop till allma have unique data elements and size 16x16, for such what would be the required size of C?

[Jan]

The code removed from the original question:

clear all;clc;
%create the first quadrant of matrix
r=0.2;x(1,1)=0.8;
for i=2:64
x(i)=r+(1-x(i-1))^2;%The first equation
end
A=x;
   for i=1: 64
     ZA=A(i);
     ssA(i)=round(mod(ZA*10^5,256));%To make the values integer between 0 - 255
   end
  A1=reshape(ssA,8,[]);
   for i=1:8
    for j=1:8
      allma(i,j)=A1(i,j);%Add the values to the large matrix to represent the first quadrant
  end
end
  %create the second quadrant of matrix
  
  u1=0.15;u2=0.13;Y(1)=0.2; X(1)=0.6;m1=2.76;m2=3.45;n=15;
for i=1:63
    X(i+1)=m1*x(i)*(1-x(i))+u1*Y(i)^2;%The second equation
    Y(i+1)=m2*Y(i)*(1-Y(i))+u2*((X(i)^2)+X(i)*Y(i));
end
B=X;
   for i=1: 64
     ZB=B(i);
       ssB(i)=round(mod(ZB*10^5,256));%To make the values integer between 0 - 255
   end
  B1=reshape(ssB,8,[]);
  ii=1;
for i=9:16
    jj=1;
    for j=1:8
      allma(i,j)=B1(ii,jj);%Add the values to the large matrix to represent the second quadrant
      jj=jj+1;
    end
  ii=ii+1;
end
%%create the third quadrant of matrix
r = 28; b = 8/3; 
 yy(1) = 20; z0(1) = 30; Q=10;
for i=2:64
X3d(i)=Q*(Y(i-1)-X(i-1));%The thied equation
yy(i)=r*X(i-1)-yy(i-1)-X(i-1)*z0(i-1);
z0(i)=X(i-1)*yy(i-1)+b*z0(i-1);%The fourth equation
end
C=X3d;
   for i=1: 64
     ZC=X3d(i);
       ssC(i)=round(mod(ZC*10^5,256));%To make the values integer between 0 - 255
   end
  C1=reshape(ssC,8,[]);
  ii=1;
for i=1:8
    jj=1;
    for j=9:16
      allma(i,j)=C1(ii,jj);%Add the values to the large matrix to represent the third quadrant
      jj=jj+1;
    end
  ii=ii+1;
end
%%create the fourth quadrant of matrix
D=z0;
for i=1: 64
     ZD=z0(i);
       ssD(i)=round(mod(ZD*10^5,256));%To make the values integer between 0 - 255
   end
  D1=reshape(ssD,8,[]);
  ii=1;
for i=9:16
    jj=1;
    for j=9:16
      allma(i,j)=D1(ii,jj);%Add the values to the large matrix to represent the fourth quadrant
      jj=jj+1;
    end
  ii=ii+1;
end
allma =
   128   151   252   249    49   224   191   178     0    39    95   255    36   123   157   237
   192    60    40    63   172   217   235   242   128    56    46   121   250   175    96   198
   192   145    73   180    21   213   187   176   144    37   217   220   154   126   179    44
   114    69   136   100   187   223   237   243   121   132   231   242   118   100    44   156
    43    11   190   126   255   204   183   175   211   135   164    64    38    55    52   159
     2    16   212   130   200   228   239   244     8   183    44    39    63    22    28   161
    86   225    80    83   238   197   180   173    66    77   256   125    22   166   146   196
   220   174    15   154   209   232   241   245    83   162   166   108    48   116   194   115
    96     7    22   171   155   111   225   237   192    37   210    36     0     0     0     0
   216    65   140   217    91   156   150    41   128   157   194   160     0     0     0     0
   197    71   113     3   232   161   106   253   165    75   250    64     0     0     0     0
   188    35   135   128   198   169   228    78     5   252   165   128     0     0     0     0
   224     8    93   230   254    17   248    14   172    69    30     0     0     0     0     0
   193   184    99   152     2   234   140   132   159   130    41     0     0     0     0     0
   124    23    91   201    29   213   202   215   169    38   138     0     0     0     0     0
    70    71    49   112    72   153   195    59   179    87    80     0     0     0     0     0

[Rena Berman]

(Answers Dev) Restored edit

Answer 1

[Walter Roberson]

   for j=1:8
    for i=1:8
      if ismember(A1(i,j),allma(1:(j-8)*8+i-1))
        allma(i, j) = TrySomethingElse(allma, i, j)) ;
       else
         allma(i,j)=A1(i,j);%Add the values to the large matrix to represent the first quadrant
        end
    end
  end

Here, TrySomethingElse(allma, i, j) represents a call to a new function that you would write that would somehow invent a new value instead of A1(i, j) to go into allma at position i, j, with the code being careful not to duplicate anything earlier in the matrix.

Please notice that I reversed the order of the for i, for j, so that now for i is the inner loop. This change causes the matrix to be filled "down" the columns instead of across the row. That change makes it easier to test against the values that have already been stored as now the previously stored values are at consecutive linear indices and so canbe extracted in a single indexing call.