필터 지우기
필터 지우기

Find rows in MATRIX based on position of elements

조회 수: 6 (최근 30일)
Rishi Balasubramanian
Rishi Balasubramanian 2021년 1월 26일
답변: Shubham Khatri 2021년 2월 3일
Consider I have a binary matrix H
H = [1 1 0 1 1 0 0 1 0 1;
0 0 0 1 0 1 0 0 1 1;
0 1 1 0 1 0 1 0 0 1;
1 1 0 0 0 0 1 0 1 1;
0 0 1 0 0 1 0 1 0 1];
From this Matrix I am supposed to select a part which becomes E matrix
E = H(4:end, 8:end);
E = [0 1 1;
1 0 1];
Now what I need is - I need to find the rows in H which have 1s in positions equal to the positions of 1s in E
How do I achieve this in a simple way. Please help, people...
Edit - Basically the answer I need is row 1 and 2. How do I get it?
  댓글 수: 10
Rishi Balasubramanian
Rishi Balasubramanian 2021년 1월 26일
Order of rows of E are not arbitrary. E is a selection of H. I don't want anything to do in E. But i want to find the rows(1 to 4) which have values exactly same as the ones in E(Consider the columns indices of E as 8, 9, 10 itself)
Jan
Jan 2021년 1월 26일
If you are searching for the pattern:
E = [0 1 1;
1 0 1];
in the matrix:
H = [1 1 0 1 1 0 0 1 0 1;
0 0 0 1 0 1 0 0 1 1;
0 1 1 0 1 0 1 0 0 1;
1 1 0 0 0 0 1 0 1 1;
0 0 1 0 0 1 0 1 0 1];
you cannot find a matching matrix in the rows 1 and 2. As you writer: Row 1 ist matching row 5 and rows 2 is matching row 4. This means, you are looking for the E flipped vertically? This does not match the explanation "I don't want anything to do in E".
Or in other words: The pattern E does not appear anywhere in H except for the original location E were taken from.
If you know in advance, that you do not care about matchs in some specific lines, you are not searchung in H, but in H(1:end-2, :).
I suggest to restart from scratch. Obviously the leven of confusion is high. Then take a coffee and solve a sudoku. Afterwards take the time to explain clearly, what the inputs are and what you are exactly looking for. It is always harder to explain, when you know exactly what you want, because this makes it harder to imagine, that others do not have the faintest idea of it.

댓글을 달려면 로그인하십시오.

채택된 답변

Shubham Khatri
Shubham Khatri 2021년 2월 3일
Hello,
To my understanding you want to find the row number in the matrix H when there is match in matrix E.
To do this, I have converted the row of both matrix H and E in a string and then have compared them. If the value returned is a positive number, we display the row number. I have done this using 2 for loops. You can also locate the element number if you remove the size from s1 variable.
clc
H = [1 1 0 1 1 0 0 1 0 1;
0 0 0 1 0 1 0 0 1 0;
0 1 1 0 1 0 1 0 0 1;
1 1 0 0 0 0 1 0 1 1;
0 0 1 0 0 1 0 1 0 1];
E = H(4:end, 8:end);
for j=1:length(E(:,1))
a=E(j,:)
for k=1:length(H(:,1))
b=H(k,:);
s=num2str(a);
t=num2str(b);
s= s(find(~isspace(s)));
t= t(find(~isspace(t)));
s1=size((strfind(t,s)));%comparing
if s1>0
disp(k)
end
end
end
Hope it helps

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by