assign op values from matrix

Hi all

Is there a way to assign for loop values from the matrix

for e.g. for i = x:y, here the value of x and y needs to be assigned rom the values present in the matrix, lets say A.. Is there a way to do this ??

Answer 1

[Walter Roberson]

Sure.

x = randi([0 1], 1, 50);
disp(char('0'+x))

01101000011010001111111000000111000001001001000011

locs = find(x)

locs = 1×21

2 3 5 10 11 13 17 18 19 20 21 22 23 30 31 32 38 41 44 49 50

for i = locs(13) : locs(17)-1
    fprintf('x(%d) = %d\n', i, x(i));
end

x(23) = 1
x(24) = 0
x(25) = 0
x(26) = 0
x(27) = 0
x(28) = 0
x(29) = 0
x(30) = 1
x(31) = 1
x(32) = 1
x(33) = 0
x(34) = 0
x(35) = 0
x(36) = 0
x(37) = 0

[Turbulence Analysis]

Hi walter,

Thanks for a quick response.. Actually, I got some wierd need (Lol).. I need to execute for loop in sequence

I intend to assign my loop values from the herewith attched matrix. As you see, it got discontinous numbers from 1 to 10000, for instance it starts from from 10 to 19, then 120 to 150, then 238 to 247 and so on...

My need is assign the values in for loop based on +/- 5 wherever discontinuity occurs. For e.g. first dicontinuity occurs at 10, so my values in for loop should be

for i = 5:15, then it should be 115:125 etc.,

Essentially, first I need to find where the dissonccontinuity happens in MAtrix 'A', then assign values to the for loop as per +/- 5 criteria...

I will be happy to send full code, if necessary...Thanks in advance...

for i = [5:15 115:125]

[Walter Roberson]

A = [10:19, 120:150, 238:247];
mask = diff(A) == 1;
starts = strfind([0 mask], [0 1]);
icell = arrayfun(@(V) V-5:V+5, A(starts), 'uniform', 0);
ivals = [icell{:}]

ivals = 1×33

5 6 7 8 9 10 11 12 13 14 15 115 116 117 118 119 120 121 122 123 124 125 233 234 235 236 237 238 239 240

for i = ivals
    
end

[Turbulence Analysis]

Wow.. Its amazing...

Only issue is, I need to run the for loop loop in sequence. Because, for each seqeunce I have to save the average matrix, for e.g. I have to call the files 5:15, then save the average of it, continue to next sequence i.e. 116 to 125 and so on...

for i = [5: 15 116: 125]

[Walter Roberson]

A = [10:19, 120:150, 238:247];
mask = diff(A) == 1;
starts = A(strfind([0 mask], [0 1]));
for sequence = 1 : length(starts)
    for i = starts(sequence)-5:starts(sequence)+5
       do some calculations
    end
    filename = sprintf('results_%03d.mat', sequence);
    save(filename, 'AppropriateVariable')
end

[Turbulence Analysis]

Thanks a lot Walter.. It's serving the purpose perfectly